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2 years ago

Write the slope-intercept form of the line that passes through the point (1, 0) and is parallel to x-y=7.

1 answer:

6 0

The slope-intercept form of x - y = 7 is y = x - 7. The slope of that line is 1. That means the slope of the line that also goes through (1, 0) is also 1. If you use the point-slope formula, the answer you will receive is y = x - 1.

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A baseball player throws a ball from second base to home plate. How far does the player throw the ball?

Fynjy0 [20]

Answer:

The player throws 127.3 ft from second base to home plate.

Step-by-step explanation:

Given:

Distance from home to first base = 90 ft

Distance from first base to second base = 90 ft

We need to find the distance from second base to home.

Solution:

Now we can assume the complete scenario to be formed as a right angled triangle with two sides given and to find the third side.

Now by using Pythagoras theorem which states that;

Square of the hypotenuse side is equal to sum of squares of other two sides.

framing in equation form we get;

distance from second base to home = $\sqrt{90^2+90^2}= 127.27 \ ft$

Rounding to nearest tent we get;

distance from second base to home = 127.3 ft

Hence The player throws 127.3 ft from second base to home plate.

6 0

2 years ago

Evaluate the expression x^2 - y^2, if x = -3, and y= 2

Darina [25.2K]

$\\ \rm\longmapsto x^2-y^2$

$\\ \rm\longmapsto (-3)^2-(2)^2$

$\\ \rm\longmapsto 9-4$

$\\ \rm\longmapsto 5$

4 0

2 years ago

Each side of a square calendar is 6 inches long. What is the calendar's area?

forsale [732]

The area would be 36 each side is 6 inches therefore you would multiply 6 by 6 to find the area

3 0

2 years ago

Read 2 more answers

A parabola has a focus of F(2, -0.5) and a directrix of y=-1.5 P(x,y) represents any point on the parabola, while D(x, -1.5) rep

prohojiy [21]

The sketch of the parabola is attached below

We have the focus $(a,b) = (2, -0.5)$
The point $P(x,y)$
The directrix, c at $y=-1.5$

The steps to find the equation of the parabola are as follows

Step 1
Find the distance between the focus and the point P using Pythagoras. We have two coordinates; $(2, -0.5)$ and $(x,y)$ .
We need the vertical and horizontal distances to find the hypotenuse (the diagram is shown in the second diagram).
The distance between the focus and point P is given by
$\sqrt{ (x-a)^{2}+ (y-b)^{2} }$

Step 2
Find the distance between the point P to the directrix $c$ . It is a vertical distance between y and c, expressed as $y-c$

Step 3
The equation of parabola is then given as
$\sqrt{ (x-a)^{2}+ (y-b)^{2} }$ = $y-c$
$(x-a)^{2}+ (y-b)^{2}= (y-c)^{2}$ ⇒ substituting a, b and c
$(x-2)^{2}+ (y--0.5)^{2} = (y--1.5)^{2}$
$(x-2)^{2}+ (y+0.5)^{2}= (y+1.5)^{2}$ ⇒Rearranging and making $y$ the subject gives

$y= \frac{ x^{2} }{2} -2x+1$

7 0

3 years ago

Can Kayla conclude that ∆ABC and ∆EDC are similar?

Kisachek [45]

Answer:yes

Step-by-step explanation:

4 0

2 years ago