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3 years ago

Which number is the largest? 7.2 ⋅ 10−6, 3.09 ⋅ 103, 2.04 ⋅ 104, 5 ⋅ 103

Mathematics

2 answers:

WITCHER [35]3 years ago

7 0

7.2 x 10 - 6 = 72 - 6 = 66
3.09 x 103 = 318.27
2.04 x 104 = 212.16
5 x 103 = 309

3.09 x 103 is the largest

mars1129 [50]3 years ago

5 0

Answer:

7.2 x 10 - 6 = 72 - 6 = 66

3.09 x 103 = 318.27

2.04 x 104 = 212.16

5 x 103 = 309

3.09 x 103 is the largest

Step-by-step explanation:

I appreciate you asking for help, speaking of that I hope this helps you! Have a good day!

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List five bias questions.

ki77a [65]

Go to Calvin. Edu hope this helps.

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3 years ago

Consider a collection of envelopes consisting of 1 red envelope, 3 blue envelopes, 2 green envelopes, and 3 yellow envelopes if

nasty-shy [4]

Answer:

the probability that at least one envelope is a yellow envelope is 16/21

Step-by-step explanation:

The probability that at least one envelope is a yellow envelope is P(Y);

P(Y) = 1 - P(Y)'

P(Y)' is the probability that no envelope is a yellow envelope.

Given;

red envelope = 1

blue envelopes = 3

green envelopes = 2

yellow envelopes = 3

Total = 9

Number of non-yellow envelope = 9 -3 = 6

(6 envelope are not yellow)

P(Y)' = P1 × P2 × P3

Since there is no replacement;

P(Y)' = 6/9 × 5/8 × 4/7

P(Y)' = 5/21

From equation 1;

P(Y) = 1 - 5/21

P(Y) = 16/21

the probability that at least one envelope is a yellow envelope is 16/21.

8 0

3 years ago

3RD TIME PLS REALLY NEED THIS

tatyana61 [14]

Answer:

Part A: a) Corresponding angles

Part B: b) 12x - 10 = 10x + 8

Part C: x = 9

m<1 = 98

m<2 = 82

Explanation:

Since they're corresponding angles, they're equal to each other:

12x - 10 = 10x + 8

2x = 18

x = 9

m<1:

12(9) - 10 = 98

m<2:

98 + y = 180

y = 82

6 0

3 years ago

Read 2 more answers

Recorded here are the germination times (in days) for ten randomly chosen seeds of a new type of bean. See Attached Excel for Da

alexgriva [62]

Answer:

The 99% confidence interval for the mean germination time is (12.3, 19.3).

Step-by-step explanation:

The question is incomplete:

Recorded here are the germination times (in days) for ten randomly chosen seeds of a new type of bean: 18, 12, 20, 17, 14, 15, 13, 11, 21, 17. Assume that the population germination time is normally distributed. Find the 99% confidence interval for the mean germination time.

We start calculating the sample mean M and standard deviation s:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{10}(18+12+20+17+14+15+13+11+21+17)\\\\\\M=\dfrac{158}{10}\\\\\\M=15.8\\\\\\$

$s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{9}((18-15.8)^2+(12-15.8)^2+(20-15.8)^2+. . . +(17-15.8)^2)}\\\\\\s=\sqrt{\dfrac{101.6}{9}}\\\\\\s=\sqrt{11.3}=3.4\\\\\\$

We have to calculate a 99% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=15.8.

The sample size is N=10.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{3.4}{\sqrt{10}}=\dfrac{3.4}{3.162}=1.075$