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3 years ago

Does the size of parachute affect the speed and why

Mathematics

1 answer:

Kryger [21]3 years ago

6 0

Yes it does , more mass area = less space

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10. Given m and b, write the equation of the line:<br><br> m=-4; b=2

steposvetlana [31]

Answer:

y= -4x + 2

Step-by-step explanation:

Y= mx + b is used to find the equation of the line

m=-4 a d b= 2

So, you put them into the equation.

6 0

2 years ago

What is the equation of the following line

Alex_Xolod [135]

Its B
rise over run dictates that its 2/8 which simplifies to 1/4
and its at an upward angle from left to right therefore its positive.

3 0

3 years ago

Read 2 more answers

Can someone help me pls

qaws [65]

Answer:Example1: 2 and 2 1/2

The mark that is closest to the right end of the glue stick is for 2 1/2 inches.

Answer on last part is 2 1/2 inches

Example 2: 1 2/4 and 1 3/4

The mark that is closest to the right end of the paper clip is for 1 3/4

Answer on last part is 1 3/4

Step-by-step explanation: the ruler is split into halves and fourths between the whole numbers the longer lines are halves shorter are fourths.

5 0

3 years ago

write an equation of the perpendicular bisector of the line segment whose endpoints are (-1,1) and (7,-5)

gladu [14]

Find midpoint of segment.
(-1,1), (7,-5)
$x= \frac{-1+7}{2}=3,y= \frac{1+(-5)}{2}=-2$

Find slope of line which passes through (-1,1) and (7,-5).
$m= \frac{-5-1}{7-(-1)}= \frac{-6}{8}=- \frac{3}{4}$

The slope of perpendicular line is negative reciprocal value of m.
$m_{\perp}=- \frac{1}{m} =- \frac{1}{- \frac{3}{4} } = \frac{4}{3}$

Write quation of line which slope is $\frac{4}{3}$ and passes throug the point (3,-2).
$m=\frac{4}{3},x_1=3,y_1=-2
\\y-y_1=m(x-x_1)
\\
\\y-(-2)=\frac{4}{3}(x-3)
\\
\\y+2=\frac{4}{3}x-\frac{8}{3}
\\
\\3y+6=4x-8
\\4x-3y-14=0$

3 0

2 years ago

Find the exponential function that passes through the points (2,80) and (5,5120)

juin [17]

Answer:

y = 5·4^x

Step-by-step explanation:

If you have two points, (x1, y1) and (x2, y2), whose relationship can be described by the exponential function ...

y = a·b^x

you can find the values of 'a' and 'b' as follows.

Substitute the given points:

y1 = a·b^(x1)

y2 = a·b^(x1)

Divide the second equation by the first:

y2/y1 = ((ab^(x2))/(ab^(x1)) = b^(x2 -x1)

Take the inverse power (root):

(y2/y1)^(1/(x2 -x1) = b

Use this value of 'b' to find 'a'. Here, we have solved the first equation for 'a'.

a = y1/(b^(x1))

In summary:

b = (y2/y1)^(1/(x2 -x1))
a = y1·b^(-x1)

For the problem at hand, (x1, y1) = (2, 80) and (x2, y2) = (5, 5120).

b = (5120/80)^(1/(5-2)) = ∛64 = 4

a = 80·4^(-2) = 80/16 = 5

The exponential function is ...

y = 5·4^x

3 0

2 years ago