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cupoosta [38]
3 years ago
6

Please show steps. explantion would be good too

Mathematics
2 answers:
kati45 [8]3 years ago
5 0
<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Assuming the roles will be filled in order, this is how you would figure it out

(e.g. role 1 is assigned, then role 2 is assigned)

There would be 9 possible candidates for the first position

Once that position has been decided, the second position will have 8 possible candidates

FOr the third position, there will be 7 possible candidates

6 possible candidates for the fourth position

5 possible candidates for the fifth position

To find all the different possibilities, you need to multiply the number of possible candidates for each role together:

9 x 8 x 7 x 6 x 5 = 15120

It would be option B

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

vredina [299]3 years ago
4 0

Hey there!

"A student government  has <u>5</u> <u>positions</u> to fill and there are<u> 9 candidates</u>  running for any one of the positions. How many different possibilities are there for the <u>5 positions</u>?"

  1. <em>Highlight your key terms (this step helps you understand the question/ word problem better). We are going a little bit downward. until we find out what we're going to do to solve this equation :)</em>
  2. We have about 9 possible candidates for your "First position"
  3. Your "second position" would probably most likely going to be 8, I believe
  4. For your "third position" you would have it as 7
  5. For your "fourth position" you would most likely have about 6
  6. And last but not least for your "fifth position" the amount of candidates would most likely be 5
  7. <em>Now that we have that portion out of the way, let's solve for your answer! </em>

                   - \bold{Your \ steps\downarrow}

  • \bold{9\times8\times7\times6\times5}
  • \bold{9\times8=72}
  • \bold{72\times7\times6\times5}
  • \bold{72\times7=504}
  • \bold{504\times6\times5}
  • \bold{504\times6=3,024}
  • \bold{3,024\times5=15,120}
  • \boxed{\boxed{\bold{Your \ Answer:15,120}}}\checkmark

Good luck on your assignment and enjoy your day!

~\bold{\frak{LoveYourselfFirst:)}}

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Answer:

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Step-by-step explanation:

We want to solve for x in 2x^2+3x-7=x^2+5x+39

You need to group and combine like terms and write in standard form:

2x^2-x^2+3x-5x-7-39=0

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The solution can be obtained using the quadratic formula.

x=\frac{-b\pm \sqrt{b^2-4ac} }{2a}

We substitute the coefficients to get:

x=\frac{--2\pm \sqrt{(-2)^2-4*1*-46} }{2*1}

x=\frac{2\pm \sqrt{4+4*46} }{2}

x=\frac{2\pm \sqrt{4*47} }{2}

x=\frac{2\pm2\sqrt{47} }{2}

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Answer: (2, 5)

Step-by-step explanation:

y = 2x + 1 y = 4x − 3

Eliminate the equal sides of each equation and combine.

2x + 1 = 4x − 3

Solve 2x + 1 = 4x − 3 for x.

Move all terms containing x to the left side of the equation.

Subtract 4x from both sides of the equation.

2x + 1 − 4x = −3

Subtract 4x from 2x.

−2x + 1 = −3

Move all terms not containing x to the right side of the equation.

Subtract 1 from both sides of the equation.

−2x = −3 − 1

Subtract 1 from −3.

−2x = −4

Divide each term by −2 and simplify.

x = 2

Evaluate y when x = 2.

Substitute 2 for x. y = 4 (2) − 3

Simplify 4 (2) − 3.

Multiply 4 by 2.

y = 8 − 3

Subtract 3 from 8.

y = 5

The solution to the system is the complete set of ordered pairs that are valid solutions.

(2, 5)

The result can be shown in multiple forms.

Point Form:

(2, 5)

Equation Form:

x = 2, y = 5

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riadik2000 [5.3K]
Combine like terms
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