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SIZIF [17.4K]
3 years ago
11

How Do you evaluate -11

Mathematics
1 answer:
vesna_86 [32]3 years ago
7 0
You find its absolute value which is 11

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15x squared minus 4c minus 4
hodyreva [135]

This cannot be factored or factored by grouping.

7 0
3 years ago
What is the solution of -x+4>2
Svetradugi [14.3K]

There is no single solution but there is a group of solutions also known as the interval.

-x+4>2 \\-x>-2 \\x

This can be written with an interval.

x\in(-\infty, 2)

Hope this helps.

r3t40

6 0
3 years ago
In science class, Jada uses a graduated cylinder with water in it to measure the volume of some marbles. After dropping in 4 mar
Monica [59]

Answer:

1. 0.17 because ur mom

2. 9.52 cus im better

3. 11.53 cus ur trash

4. yes cus constant rate of change

Step-by-step explanation:

7 0
2 years ago
Dùng tiền gửi ngân hàng trả tiền cho người bán 100.000.000
goldfiish [28.3K]

Answer:

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Step-by-step explanation:

I dont know the answer to this question.....

5 0
2 years ago
In a survey of 1000 large corporations, 260 said that, given a choice between a job candidate who smokes and an equally qualifie
Usimov [2.4K]

Answer:

The 95% confidence interval for the proportion of corporations preferring a nonsmoking candidate is (0.2328, 0.2872)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 1000, p = \frac{260}{1000} = 0.26

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.26 - 1.96\sqrt{\frac{0.26*0.74}{1000}} = 0.2328

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.26 + 1.96\sqrt{\frac{0.26*0.74}{1000}} = 0.2872

The 95% confidence interval for the proportion of corporations preferring a nonsmoking candidate is (0.2328, 0.2872)

4 0
2 years ago
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