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3 years ago

9

Can anyone help me with this question ?

2 answers:

adell [148]3 years ago

8 0

To calculate the median, all you have to do is line them up in ascending order. So from least to greatest. Then you look for the number that's in the middle, that will be your median.

So first line them up in ascending order

11, 18, 23, 32, 33, 41, 41, 54, 56, 58, 67, 70

In this example, the median would be 41 (we have two 41s in the middle but if they weren't the same number, you'd add the two middle numbers together and divide by 2, but since we don't have to do that, your answer would just be 41).

So the answer is 41.

Nuetrik [128]3 years ago

6 0

The answer is C 41 because those two numbers are in the middle when arranging them

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$0.071,1.928$

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Downtown Store North Mall Store

Sample size n 25 20

Sample mean $\bar{x}$ $9 $8

Sample standard deviation s $2 $1

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$\bar{x_1}=9\\ \bar{x_2}=8$

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Standard error of difference of means = $\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}$

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Standard error of difference of means = $0.458$

Degree of freedom = $\frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}$

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Degree of freedom =36

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Confidence interval = $(x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)$

Confidence interval = $1-(2.0280)\times 0.458,1+(2.0280)\times 0.458$

Confidence interval = $0.071,1.928$

Hence Option A is true

Confidence interval is $0.071,1.928$

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3 years ago