Answer:
P(system works) = 0.6144
Step-by-step explanation:
Each compoent has an 80% = 0.8 probability of working correctly.
1 and 2
We need at least one of them working.
Either neither works, or at least one works.
Each one has a 1 - 0.8 = 0.2 probability of not working.
0.2*0.2 = 0.04
0.04 of neither working.
1 - 0.04 = 0.96 probability of at least one working
3 and 4
We need both to work, each with a 0.8 probability.
Calculate P(system works).
At least one of the first two, with 0.96 probability
3 and 4, each with 0.8 probability.
0.96*0.8*0.8 = 0.6144
So
P(system works) = 0.6144
Answer: distributive
Step-by-step explanation: minus from both sides and you'll have the answer.
Answer:
Domain:
(
−
∞
,
∞
)
,
{
x
|
x
∈
R
}
(-∞,∞),{x|x∈ℝ}
Range:
[
−
4
,
∞
)
,
{
y
|
y
≥
−
4
}
[-4,∞),{y|y≥-4}
Step-by-step explanation:
Answer:
x = 34 candies
24+10= 34
ur welcome plz mark brainliest
You would multiply each side by -2 so the answer is x=-28