All categories

3 years ago

Ramal filled 3 pages in a stamp album.This is one sixth of the pages in the album.How many pages are their in ramals stamp album

Mathematics

2 answers:

padilas [110]3 years ago

8 0

Well

x/6=3/*6
x=18

There are 18 pages in Ramals stamp album

natulia [17]3 years ago

6 0

Answer: There are 18 pages in the Ramal's stamp album.

Step-by-step explanation:

Given: The number of pages filled by Ramal in each stamp album = 3

The part of album filled by Ramal = $\frac{1}{6}$

Let x be the total number of pages he filled the, we have

$\frac{x}{6}=3$

Multiply 6 on the both sides , we get

$x=3\times6\\\Rightarrow\ x=18$

hence, there are 18 pages in the Ramal's stamp album.

You might be interested in

A . ( 12 ) x ( − 16 ) + 16 b . ( − 34 ) ÷ ( − 23 ) + 14 c . ( − 45 ) ÷ ( − 15 ) + 13 d . ( 23 ) - ( − 16 ) 13 e . ( − 42 ) + ( -

MA_775_DIABLO [31]

<h2>Question</h2>

Simplify the following

A . ( 12 ) x ( − 16 ) + 16

b . ( − 34 ) ÷ ( − 23 ) + 14

c . ( − 45 ) ÷ ( − 15 ) + 13

d . ( 23 ) - ( − 16 ) - 13

e . ( − 42 ) + ( - 16 ) ÷ 13

<h2>Answer:</h2>

(A) -176

(B) $\frac{402}{23}$

(D) 26

(E) $\frac{-562}{13}$

<h2>Step-by-step explanation:</h2>

(A)

( 12 ) x ( − 16 ) + 16

Following the rules of BODMAS

<em>=> Solve the brackets first</em>

12 x -16 + 16

<em>=> Next, solve the multiplication(x)</em>

-192 + 16

<em>=> Solve the addition and subtraction</em>

-176

(B)

( − 34 ) ÷ ( − 23 ) + 14

Following the rules of BODMAS

<em>=> Solve the brackets first</em>

-34 ÷ -23 + 14

<em>=> Next, solve the division(÷)</em>

$\frac{-34}{-23}$ + 16

The negative signs can cancel out.

$\frac{34}{23}$ + 16

<em>=> Solve the fraction</em>

$\frac{34}{23}$ + $\frac{16}{1}$

$\frac{34 + 368}{23}$

$\frac{402}{23}$

(C)

( − 45 ) ÷ ( − 15 ) + 13

Following the rules of BODMAS

<em>=> Solve the brackets first</em>

-45 ÷ -15 + 13

<em>=> Next, solve the division(÷)</em>

$\frac{-45}{-15}$ + 13

The negative signs can cancel out.

$\frac{45}{15}$ + 13

3 + 13

<em>=> Solve the addition</em>

3 + 13 = 16

(D)

( 23 ) - ( − 16 ) - 13

Following the rules of BODMAS

<em>=> Solve the brackets first</em>

23 - -16 - 13

23 + 16 - 13

<em>=> Next solve the addition</em>

39 - 13

<em>=> Next solve the subtraction</em>

39 -13 = 26

(E)

( − 42 ) + ( - 16 ) ÷ 13

Following the rules of BODMAS

<em>=> Solve the brackets first</em>

-42 + -16 ÷ 13

-42 - 16 ÷ 13

<em>=> Next solve the division</em>

-42 - 16 ÷ 13

-42 - $\frac{16}{13}$

<em>=> Next solve the fraction</em>

$\frac{-42}{1}$ - $\frac{16}{13}$

$\frac{-546-16}{13}$

$\frac{-562}{13}$

4 0

3 years ago

9x - 4y? +72x–24y— 36–0

earnstyle [38]

Not is posible because no exist a igualty

3 0

4 years ago

Please help ASAP ‼️‼️‼️‼️‼️‼️

nydimaria [60]

Answer:

Step-by-step explanation:

vertex of g(x) is (0, 0), so:

$g(x)=a(x-0)^2+0\\\\g(x)=ax^2 \qquad and\qquad (2,\,1)\in g(x)\\\\1=a\cdot2^2\\1=4a\\a=\frac14\\\\g(x)=\frac14x^2=(\frac12x)^2$

7 0

3 years ago

I’ll give brainley and 10 points

Licemer1 [7]

Answer:At a charity fund raiser , adult tickets were sold for 8$ children each and children’s tickets were sold at 2$ each. write an algebraic expression for the total amount raised from the sale of tickets. At a charity fund raiser , adult tickets were sold for 8$ children each and children’s tickets were sold at 2$ each. write an algebraic expression for the total amount raised from the sale of tickets. How much money was raised if the fundraiser sold 238 adult tickets and 375 children’s tickets?

Step-by-step explanation:

2,654$

Step-by-step explanation:

8a + 2c

8 x 238 = 1,904

2 x 375 = 750

750 + 1,904 = 2,654

2,654$

5 0

3 years ago

A salad made such that the difference between twice the ounces of greens and the ounces of carrots is at least 3. Also, the sum

AysviL [449]

Answer:

The graph of 3rd picture is correct Option.

Step-by-step explanation:

Let x =green and y = carrots

We make equations of the given sentences and then plot them to find the correct answer.

The equation for A salad made such that the difference between twice the ounces of greens and the ounces of carrots is at least 3 is

2x-y ≥ 3

The equation for the sum of the ounces of greens and twice the ounces of carrots is less than 4.

x+2y < 4

We plot both the equations and gain the graph.

The graph is attached in the figure.

The graph of 3rd picture is correct Option.

7 0

4 years ago