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murzikaleks [220]
3 years ago
13

A . ( 12 ) x ( − 16 ) + 16 b . ( − 34 ) ÷ ( − 23 ) + 14 c . ( − 45 ) ÷ ( − 15 ) + 13 d . ( 23 ) - ( − 16 ) 13 e . ( − 42 ) + ( -

16 ) ÷ 13
Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
4 0
<h2>Question</h2>

Simplify the following

A . ( 12 ) x ( − 16 ) + 16

b . ( − 34 ) ÷ ( − 23 ) + 14

c . ( − 45 ) ÷ ( − 15 ) + 13

d . ( 23 ) - ( − 16 ) - 13

e . ( − 42 ) + ( - 16 ) ÷ 13

<h2>Answer:</h2>

(A) -176

(B) \frac{402}{23}

(C) 16

(D) 26

(E) \frac{-562}{13}

<h2>Step-by-step explanation:</h2>

(A)

( 12 ) x ( − 16 ) + 16

Following the rules of BODMAS

<em>=> Solve the brackets first</em>

12 x -16 + 16

<em>=> Next, solve the multiplication(x)</em>

-192 + 16

<em>=> Solve the addition and subtraction</em>

-176

(B)

( − 34 ) ÷ ( − 23 ) + 14

Following the rules of BODMAS

<em>=> Solve the brackets first</em>

-34 ÷ -23 + 14

<em>=> Next, solve the division(÷)</em>

\frac{-34}{-23} + 16

The negative signs can cancel out.

\frac{34}{23} + 16

<em>=> Solve the fraction</em>

\frac{34}{23} + \frac{16}{1}

\frac{34 + 368}{23}

\frac{402}{23}

(C)

( − 45 ) ÷ ( − 15 ) + 13

Following the rules of BODMAS

<em>=> Solve the brackets first</em>

-45 ÷ -15 + 13

<em>=> Next, solve the division(÷)</em>

\frac{-45}{-15} + 13

The negative signs can cancel out.

\frac{45}{15} + 13

3 + 13

<em>=> Solve the addition</em>

3 + 13 = 16

(D)

( 23 ) - ( − 16 ) - 13

Following the rules of BODMAS

<em>=> Solve the brackets first</em>

23 - -16 - 13

<em>=> Next, - - will give + </em>

23 + 16 - 13

<em>=> Next solve the addition</em>

39 - 13

<em>=> Next solve the subtraction</em>

39 -13 = 26

(E)

( − 42 ) + ( - 16 ) ÷ 13

Following the rules of BODMAS

<em>=> Solve the brackets first</em>

-42 + -16 ÷ 13

<em>=> Next, + - will give -</em>

-42 - 16 ÷ 13

<em>=> Next solve the division</em>

-42 - 16 ÷ 13

-42 - \frac{16}{13}

<em>=> Next solve the fraction</em>

\frac{-42}{1} - \frac{16}{13}

\frac{-546-16}{13}

\frac{-562}{13}

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<h3>How to calculate the surface area of a composite figure?</h3>

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That ∑ sign shows "sum"

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