Answer:
It is not a good model because neither point lies on the line.
Step-by-step explanation:
We can test each point on the equation of the line.
7x - 10y = 3
Point: (8, 5)
7(8) - 10(5) = 56 - 50 = 6
The left side equals 6, not 3, so point (8, 5) is not on that line.
Point: (-12, -9)
7(-12) - 10(-9) = -84 + 90 = 6
The left side equals 6 again, but the right side is 3, not 6.
Answer: It is not a good model because neither point lies on the line.
Answer:
-4.65< -4 and 2/5
Step-by-step explanation:
To solve, this we can convert the fraction -4 and 2/5 into a decimal so that the values can be more easily compared. When we do this, we get the result that -4 and 2/5 equals -4.4. Now we can clearly see which value is greater because they are written in the same form:
-4.65<-4.4
-4.65<-4 2/5
<span>(a) This is a binomial
experiment since there are only two possible results for each data point: a flight is either on time (p = 80% = 0.8) or late (q = 1 - p = 1 - 0.8 = 0.2).
(b) Using the formula:</span><span>
P(r out of n) = (nCr)(p^r)(q^(n-r)), where n = 10 flights, r = the number of flights that arrive on time:
P(7/10) = (10C7)(0.8)^7 (0.2)^(10 - 7) = 0.2013
Therefore, there is a 0.2013 chance that exactly 7 of 10 flights will arrive on time.
(c) Fewer
than 7 flights are on time means that we must add up the probabilities for P(0/10) up to P(6/10).
Following the same formula (this can be done using a summation on a calculator, or using Excel, to make things faster):
P(0/10) + P(1/10) + ... + P(6/10) = 0.1209
This means that there is a 0.1209 chance that less than 7 flights will be on time.
(d) The probability that at least 7 flights are on time is the exact opposite of part (c), where less than 7 flights are on time. So instead of calculating each formula from scratch, we can simply subtract the answer in part (c) from 1.
1 - 0.1209 = 0.8791.
So there is a 0.8791 chance that at least 7 flights arrive on time.
(e) For this, we must add up P(5/10) + P(6/10) + P(7/10), which gives us
0.0264 + 0.0881 + 0.2013 = 0.3158, so the probability that between 5 to 7 flights arrive on time is 0.3158.
</span>
Answer:
2 cases of soya bean milk will have the same volume as 1 case of fruit juice.
Step-by-step explanation:
Let the case of soya beans drink be x and let the case of fruit juice be y
We are told that the room can store either 10 cases of soya beans drink and 8 cases of fruit juice or 4 cases of soybeans drink and 11 cases of fruit juice.
This means that;
10x + 8y = 4x + 11y
Rearranging, we have;
10x - 4x = 11y - 8y
6x = 3y
Thus;
y = 6x/3
y = 2x
This means that 2 cases of soya bean milk will have the same volume as 1 case of fruit juice.
There are 1000 grams in a kilogram.
9000 grams/1000 grams per kg=9 kg
Finl answer: 9kg
