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The value of x in x^yz = y^2 is
The equation is given as:
x^yz = y^2
Rewrite the equation properly as follows
Take the yz root of both sides
Apply the law of indices
Divide yz by yz
Hence, the value of x in x^yz = y^2 is
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Answer:
Z-score = -1.285
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 17.6 seconds
Standard Deviation, σ = 2.1 seconds
Formula:
For x = 14.9, we have:
A z-score to be unusual if its z-score is less than -2.00 or greater than 2.00.
Thus, the z-score is not unusual as it lies in the range [-2.00, 2.00]