Which of the following represents a focus of the equation y2 + 4 = 4y +x

Which fraction is equivalent to 6/8. A.8/9. B.4/6. C.9/12. D.8/10

DaniilM [7]

Answer:

Explanation:

6/8 simplifies to 3/4

3 × 3 = 9

4 × 3 = 12

Since they are both multiples of 3, it's equivalent to 6/8.

7 0

2 years ago

Assumptions of a regression model can be evaluated by plotting and analyzing the ____________

Gala2k [10]

The assumptions of a regression model can be evaluated by plotting and analyzing the error terms.

Important assumptions in regression model analysis are

There should be a linear and additive relationship between dependent (response) variable and independent (predictor) variable(s).
There should be no correlation between the residual (error) terms. Absence of this phenomenon is known as auto correlation.
The independent variables should not be correlated. Absence of this phenomenon is known as multi col-linearity.
The error terms must have constant variance. This phenomenon is known as homoskedasticity. The presence of non-constant variance is referred to heteroskedasticity.
The error terms must be normally distributed.

Hence we can conclude that the assumptions of a regression model can be evaluated by plotting and analyzing the error terms.

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4 0

2 years ago

In a group of 700 people only 5% of them have red hair how many people hade red hair

Svetradugi [14.3K]

35 people have red hair. Do 700 times 0.05.

3 0

3 years ago

What is 112.491 written in word form?

bearhunter [10]

Answer:

112.491 = one hundred twelve and four hundred ninety-one

thousandths.

Step-by-step explanation:

6 0

2 years ago

Although companies would like consumers to believe that Identity theft protection is an

stiks02 [169]

The obtained answers for the given frequency distribution are:

(a) The formula for the mean in sigma notation is $\bar x =\frac{1}{n} \sum X_i$ where n is the number of observations; $X_i$ are the n observations.

The mean for the given monthly plan price is $16.1.

(b) The frequency distribution for given data is {$9.99 - 2; $10 - 5; $12 - 1; $12.75 - 2; $14.99 - 6; $20 - 4; $25 - 5}

(c) The formula for the mean using the frequency distribution table is $\bar x = \frac{1}{N}\sum f_ix_i$ where $N =\sum f_i$ and on applying this formula for the given data, the mean is $16.1.

(d) The median for the given data is $m_e = 14.99$ , and the mode for the given data is $14.99

<h3>What are the mean, median, and mode for a frequency distribution?</h3>

The frequency distribution has sample observations $x_i$ and frequencies $f_i$ .

Then, the mean is calculated by

$\bar x = \frac{1}{N}\sum f_ix_i$

Where $N =\sum f_i$ (Sum of frequencies)

The median is calculated by

$m_e=\left \{ {{x_{k}} \ if \ n = 2k+1 \atop {\frac{x_{k}+x_{k+1}}{2}} \ if \ n =2k} \right.$

The mode is calculated by

Mode = highest frequency value

<h3>Calculation:</h3>

The given list of data is

{$14.99, $12.75, $14.99, $14.99, $9.99, $25, $25, $10, $14.99, $10, $20, $10, $20, $14.99, $10, $25, $20, $12, $14.99, $25, $25, $20, $12.75, $10, $9.99}

(a) Formula for the mean using sigma notation and use it to calculate the mean:

The formula for the mean is

$\bar x =\frac{1}{n} \sum X_i$

Where n = 25; $X_i$ - n observations

On substituting,

Mean $\bar x$

=1/25(14.99+12.75+14.99+14.99+9.99+25+25+10+14.99+10+20+10+20+14.99+10+25+20+12+14.99+25+25+20+12.75+10+9.99)

= 1/25(402.42)

= 16.09 ≅ 16.1

(b) Constructing a frequency distribution for the data:

Cost - frequency - cumulative frequency

$9.99 - 2 - 2

$10 - 5 - 7

$12 - 1 - 8

$12.75 - 2 - 10

$14.99 - 6 - 16

$20 - 4 - 20

$25 - 5 - 25

Sum of frequencies N = 25;

(c) Using frequency distribution, calculating the mean:

The formula for finding the mean using frequency distribution is

$\bar x = \frac{1}{N}\sum f_ix_i$

Where N = 25;

On substituting,

$\bar x$ = 1/25 (2 × 9.99 + 5 × 10 + 1 × 12 + 2 × 12.75 + 6 × 14.99 + 4 × 20 + 5 × 25)

= 1/25 (402.42)

= 16.09 ≅ 16.1

Therefore, the mean is the same as the mean obtained in option (a).

(d) Calculating the median and the mode:

Since N = 25(odd) i.e., 2· 12 + 1; k = (12 + 1)th term = 13th term

So, the median $m_e$ = 14.99. (frequency at 13th term)

Since the highest frequency is 6 occurred by the cost is $14.99,

Mode = 14.99

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7 0

2 years ago