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ra1l [238]
3 years ago
10

Mimi needs eleven 18-inch pieces of rhinestone ribbonShe purchased 5 yards of the ribbon shown at the rightIf Mimi purchases the

additional ribbon she needs, what will be the total cost of all the ribbon?
Data: $6 per yard, $55 for the whole spool, the whole spool is 10 yards.
Mathematics
2 answers:
prisoha [69]3 years ago
8 0

Answer:

$33

Step-by-step explanation:

Given:

Mimi needs eleven 18-inch pieces of rhinestone ribbon.

She purchased 5 yards of the ribbon.

Mimi purchases the additional ribbon she needs.

Data: $6 per yard, $55 for the whole spool, the whole spool is 10 yards.

Question asked:

What will be the total cost of all the ribbon?

Solution:

<u>As Mimi needs eleven 18-inch pieces of rhinestone ribbon:-</u>

Mimi needs total inches of ribbon = 18 inches \times 11 = 198 inches

Now convert it into yard:

36 inches = 1 yard

1 inch = \frac{1}{36}\ yard

198 inches = \frac{1}{36}\times198=5.5\ yard

Cost of 1 yard = $6

Cost of 5.5 yard = $6 \times 5.5 = $33

Thus, total cost of all the ribbon is $33.

Pie3 years ago
5 0

Answer:

5.5

Step-by-step explanation:

you mulitlply 11 by 18 you get 198 inches

rember 1 yard equals 36 inches now divided 198nby 36 and

then you get 5.5

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swat32

Answer:

<em>The percentage of males are not at least 172 pounds</em>

P(X⁻ ≥ 172) = 0.26

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that 74% of 19 -year -old males are at least 172 pounds

Let 'X' be a random variable in a binomial distribution

P( X≥172) = 74% = 0.74

<em>we have to find that the percentage of males are not at least 172 pounds</em>

<u><em>Step(ii):-</em></u>

<em>The probability of males are not at least 172 pounds</em>

P(X⁻≥172) = 1- P( X≥172)

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<em>                  = 0.26</em>

<u><em>Final answer:-</em></u>

<em>The percentage of males are not at least 172 pounds</em>

P(X⁻ ≥ 172) = 0.26

<u><em></em></u>

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