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ra1l [238]
3 years ago
10

Mimi needs eleven 18-inch pieces of rhinestone ribbonShe purchased 5 yards of the ribbon shown at the rightIf Mimi purchases the

additional ribbon she needs, what will be the total cost of all the ribbon?
Data: $6 per yard, $55 for the whole spool, the whole spool is 10 yards.
Mathematics
2 answers:
prisoha [69]3 years ago
8 0

Answer:

$33

Step-by-step explanation:

Given:

Mimi needs eleven 18-inch pieces of rhinestone ribbon.

She purchased 5 yards of the ribbon.

Mimi purchases the additional ribbon she needs.

Data: $6 per yard, $55 for the whole spool, the whole spool is 10 yards.

Question asked:

What will be the total cost of all the ribbon?

Solution:

<u>As Mimi needs eleven 18-inch pieces of rhinestone ribbon:-</u>

Mimi needs total inches of ribbon = 18 inches \times 11 = 198 inches

Now convert it into yard:

36 inches = 1 yard

1 inch = \frac{1}{36}\ yard

198 inches = \frac{1}{36}\times198=5.5\ yard

Cost of 1 yard = $6

Cost of 5.5 yard = $6 \times 5.5 = $33

Thus, total cost of all the ribbon is $33.

Pie3 years ago
5 0

Answer:

5.5

Step-by-step explanation:

you mulitlply 11 by 18 you get 198 inches

rember 1 yard equals 36 inches now divided 198nby 36 and

then you get 5.5

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3 years ago
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The graph below describes the journey of a train between two cities.
Veseljchak [2.6K]

Answer:

[A] Acceleration in first 15 min = 200  km/h²

[B] Distance between two cities = 125 km

[C] Average Speed of journey =  62.5  km/hr

Step-by-step explanation:

To Solve:

Acceleration in first 15 min

Distance between two cities  

Average speed of journey

Solve:

[A] Work out the acceleration, in km/h?, in the first 15 mins.

Each horizontal block is 1/8 hr = 7.5 min

Each vertical block is 10 km/hr

Time                     Velocity  km/hr

0 Min  ( 0 hr)            0

15 Min (1/4 hr)           50

45 Min (3/4 hr)         50

60 MIn  ( 1 hr)            100

90 Min  ( 3/2 hr)        100

120 Min ( 2hr)            0

Acceleration in first 15 min  (1/4 hr)  =  (50 - 0)/(1/4 - 0)  = 50/(1/4)

= 200  km/h²

Hence, Answer for [A] = 200  km/h²

[B] Work out the distance between the two cities. $60 Velocity (in km/h)

= (1/2)(0 + 50)(1/4 - 0)  + 50 * (3/4 - 1/4)  + (1/2)(50 + 100)(1 - 3/4)  + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)

=  25/4  + 25 + 75/4   + 50 + 25

= 125

Distance between two cities = 125 km

[C] Work out the average speed of the train during 20 the journey.

Average Speed of journey = 125/2  = 62.5  km/hr

[RevyBreeze]

5 0
3 years ago
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Aneli [31]

Answer:

150 minutes

Step-by-step explanation:

First we have to express all these fractions of an hour in minutes, then add them and get the total of minutes.

To pass these numbers in hours to minutes, we only have to multiply by 60 because one hour has 60 minutes.

3/4 h =

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5/6 h =

5/6 * 60 = 50m

11/12 h =

11/12 * 60 = 55m

to calculate the total number of minutes we have to add the 3 values ​​that we have

45m + 50m + 55m = 150m

8 0
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