Answer:
21 ft by 66 ft
Step-by-step explanation:
From the question,
P = 2(L+W)............... Equation 1
Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.
If the Length of the Field is 45 ft longer than the width,
L = 45+W............ Equation 2
Substitute Equation 2 into equation 1
P = 2(45+W+W)
P = 90+4W............. Equation 3
Given: P = 174 ft.
Substitute into equation 3
174 = 90+4W
4W = 174-90
4W = 84
W = 84/4
W = 21 ft.
Substituting the value of W into equation 2
L = 45+21
L = 66 ft.
Hence the dimensions of the playing field is 21 ft by 66 ft
This equation is in standard from unless you mean vertex standard form?
Answer:
88 problems
Step-by-step explanation:
Set this problem up as fractions
86/x = 98/100
Cross multiply
86 × 100 = x × 98
8600 = 98x
Divide both sides by 98
87.75... = x
Round to nearest whole number
87.75 rounds up to 88
88 problems
Answer:
C
Step-by-step explanation:
Sorry if its wrong bro
She practiced 630 hours in all because you multiply 18x35