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son4ous [18]
3 years ago
13

A school is planning an event to raise $1,000 for charity. The cost of organizing the event is $200. The tickets are priced at $

6 per child and $8 per adult
Mathematics
1 answer:
Travka [436]3 years ago
5 0
The school would have to raise 1200$ , by having 12 6$ tickets for kids and 6 8$ tickets per adult. which subtracted by the cost of organizing the event ( which is 200$) wouls be 1000$ for the charity fun raiser
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How do you find the exterior angle of a polygon?
trasher [3.6K]

The sum of the measures of the interior angles of a polygon with n sides is (n – 2)180.

The measure of each interior angle of an equiangular n-gon is.

If you count one exterior angle at each vertex, the sum of the measures of the exterior angles of a polygon is always 360°.

7 0
3 years ago
In the past decades there have been intensive antismoking campaigns sponsored by both federal and private agencies. In one study
DIA [1.3K]

Answer:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

p_v =2*P(Z>2.055)=0.0399    

And the best option for this case would be:

C. between 0.01 and 0.05.

Step-by-step explanation:

Information provided

X_{1}=1642 represent the number of smokers from the sample in 1995

X_{2}=1415 represent the number of smokers from the sample in 2010

n_{1}=4276 sample from 1995

n_{2}=3908 sample from 2010  

p_{1}=\frac{1642}{4276}=0.384 represent the proportion of smokers from the sample in 1995

p_{2}=\frac{1415}{3908}=0.362 represent the proportion of smokers from the sample in 2010

\hat p represent the pooled estimate of p

z would represent the statistic    

p_v represent the value for the pvalue

System of hypothesis

We want to test the equality of the proportion of smokers and the system of hypothesis are:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

The statistic is given by:

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{1642+1415}{4276+3908}=0.374  

Replacing the info given we got:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

p_v =2*P(Z>2.055)=0.0399    

And the best option for this case would be:

C. between 0.01 and 0.05.

7 0
3 years ago
HELP! I am confused since the -5 was added, so would it be the slope or would -7 be the slope?
In-s [12.5K]

Answer:

slope = 35; y-intercept = -45

Step-by-step explanation:

Function f(x) is written in the slope-intercept form, y = mx + b.

f(x) = -7x + 9

You compare it with

f(x) = mx + b, and you see that m, the slope, is -7, and b, the y-intercept is 9.

Now we deal with function h(x).

h(x) = -5(-7x + 9)

This is not written in the y = mx + b form, but we can put it in that form by distributing the -5.

h(x) = 35x - 45

Now, h(x) is written in the y = mx + b form. We see clearly that m = 35, so the slope of function h is 35. We also see that b, the y-intercept is -45.

Answer: slope = 35; y-intercept = -45

5 0
3 years ago
Can anyone help me solve these linear systems using substitution?
Andre45 [30]

Answer:

1. (2,2)

2. (-20, -1)

3. (4,3)

Step-by-step explanation:

See attached images

4 0
2 years ago
Read 2 more answers
During 2002, the average person ate 200.8 pounds of meat. How much meat does a family of 3 people eat in year?
dem82 [27]
Hi there! An average person ate 200.8 pounds of meat, so we would multiply that number by 3 to see how much meat the family ate altogether. 200.8 * 3 is 602.4. There. A family of 3 would eat 602.4 pounds of meat in a year.
4 0
4 years ago
Read 2 more answers
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