Question

James has three normal six-sided dice. he rolls all three of the dice at the same time and records the three numbers that land face up. what is the probability that the dice did not land on three-of-a-kind?

Answer 1

The answer is 1/36

The first one can be anything because we choose whatever it comes in first place.
$\frac{6}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{6}{216} = \frac{1}{36}$