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n200080 [17]
3 years ago
9

Find the slope from an equation ??? Y = -x

Mathematics
1 answer:
lord [1]3 years ago
5 0

Answer:

<h2>The answer is - 1</h2>

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

From the question the equation of the line is

y = - x

Comparing with the general equation of the line

The slope of the line is - 1

Hope this helps you

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| Solve for X<br> 8x + 1 = 49
Doss [256]
8x + 1 = 49

8x = 48

x = 6
6 0
2 years ago
A pitcher throws a 9 kg baseball in a straight line. Its momentum is 2.1 kg-m/s. What is the velocity of the
Zina [86]

Answer:

0.23\:\mathrm{m/s}

Step-by-step explanation:

The momentum of an object is given by p=mv, where m is the mass of the object and v is the velocity of the object.

What we're given:

  • object's mass m
  • object's momentum p

Substituting given values, we can solve for v:

2.1=9v,\\v=\frac{2.1}{9}\approx \boxed{0.23\:\mathrm{m/s}}

3 0
3 years ago
Consider the expression 625(5xy)^-3/ (5x)^2 y^7
andre [41]
<span>625(5xy)^-3/ (5x)^2 y^7
     
             625 
= --------------------   /  25x^2y^7
      125 x^3y^3

= 5/x^3y^3    / </span>25x^2y^7
= 5/x^3y^3   *  (1/ 25x^2y^7)
= 1 / 5x^5y^10

answer


         1
-----------------
   5x^5y^10
3 0
3 years ago
Drag expressions into order to show a way to find 3 × 56.
lina2011 [118]
As we could "drag" these together, we could then do it the easy way.

  56
+56
+56
-------
168
------------------------

Or we could also do the following:

56*3:

6*3= 18.

Carry the one. 

5*3 = 15+1 (which was carried). = 16

(16+8) = 168





7 0
3 years ago
Read 2 more answers
Does anyone know how to do this?? Help please!!!!
Doss [256]

Answer:

When we have a rational function like:

r(x) = \frac{x + 1}{x^2 + 3}

The domain will be the set of all real numbers, such that the denominator is different than zero.

So the first step is to find the values of x such that the denominator (x^2 + 3) is equal to zero.

Then we need to solve:

x^2 + 3 = 0

x^2 = -3

x = √(-3)

This is the square root of a negative number, then this is a complex number.

This means that there is no real number such that x^2 + 3 is equal to zero, then if x can only be a real number, we will never have the denominator equal to zero, so the domain will be the set of all real numbers.

D: x ∈ R.

b) we want to find two different numbers x such that:

r(x) = 1/4

Then we need to solve:

\frac{1}{4} = \frac{x + 1}{x^2 + 3}

We can multiply both sides by (x^2 + 3)

\frac{1}{4}*(x^2 + 3) = \frac{x + 1}{x^2 + 3}*(x^2 + 3)

\frac{x^2 + 3}{4} = x + 1

Now we can multiply both sides by 4:

\frac{x^2 + 3}{4}*4 = (x + 1)*4

x^2 + 3 = 4*x + 4

Now we only need to solve the quadratic equation:

x^2 + 3 - 4*x - 4 = 0

x^2 - 4*x - 1 = 0

We can use the Bhaskara's formula to solve this, remember that for an equation like:

a*x^2 + b*x + c = 0

the solutions are:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

here we have:

a = 1

b = -4

c = -1

Then in this case the solutions are:

x = \frac{-(-4) +- \sqrt{(-4)^2 - 4*1*(-1)} }{2*(1)} = \frac{4 +- 4.47}{2}

x = (4 + 4.47)/2 = 4.235

x = (4 - 4.47)/2 = -0.235

5 0
3 years ago
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