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n200080 [17]
3 years ago
9

Find the slope from an equation ??? Y = -x

Mathematics
1 answer:
lord [1]3 years ago
5 0

Answer:

<h2>The answer is - 1</h2>

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

From the question the equation of the line is

y = - x

Comparing with the general equation of the line

The slope of the line is - 1

Hope this helps you

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Draw a flow diagram to indicate the different phases in reproduction.​
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Answer:

ovulation fertilization cell division implantation conception delivery

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3 years ago
A factory produces some batteries daily. 7/8 of the batteries are packaged immediately. 2/3 of the
frozen [14]

Answer:

\[\frac{1}{24}\]

Step-by-step explanation:

Let the total number of batteries produced daily be represented by x.

7/8 of the batteries are packaged immediately.

So the total number of packaged batteries = \[\frac{7x}{8}\]

Remaining batteries = \[x-\frac{7x}{8}\]

= \[\frac{x}{8}\]

Two third of the remaining batteries are sent to charity.

So the total number of batteries sent to charity= \[\frac{2}{3} * \frac{x}{8}\]

= \[\frac{x}{12}\]

Remaining batteries are faulty.

So the total number of faulty batteries = \[\frac{x}{8} - \frac{x}{12}\]

= \[\frac{3x - 2x}{24}\]

= \[\frac{x}{24}\]

So the faction of batteries which are faulty =

= \[\frac{x}{24} \div x\]

= \[\frac{1}{24}\]

3 0
3 years ago
Heyyyyyyyyyyyyyyyyyyyyyyyyyy!
kifflom [539]
Hi how are you hope all is well
8 0
3 years ago
(3x+9)^5=32x^5<br> help solve for x
makvit [3.9K]
Answer:
x = -9

Explanation:

(3x + 9)^5 = 32x^5

(3 (x + 3))^5 = 32x^5

3^5 (x + 3)^5 = 32x^5

243(x + 3)^5 = 32x^5

243(x + 3)^5 - 32x^5 = 0

x = -9
5 0
3 years ago
Read 2 more answers
Find UV (Pic Stated Below)
natta225 [31]

Answer:

UV=29

Step-by-step explanation:

In right triangles AQB and AVB,

∠AQB = ∠AVB ...(i)  {Right angles}

∠QBA = ∠VBA ...(ii)  {Given that they are equal}

We know that sum of all three angles in a triangle is equal to 180 degree. So wee can write sum equation for each triangle


∠AQB+∠QBA+∠BAQ=180 ...(iii)

∠AVB+∠VBA+∠BAV=180 ...(iv)


using (iii) and (iv)

∠AQB+∠QBA+∠BAQ=∠AVB+∠VBA+∠BAV

∠AVB+∠VBA+∠BAQ=∠AVB+∠VBA+∠BAV  (using (i) and (ii))

∠BAQ=∠BAV...(v)


Now consider triangles AQB and AVB;

∠BAQ=∠BAV  {from (v)}

∠QBA = ∠VBA {from (ii)}

AB=AB  {common side}

So using ASA, triangles AQB and AVB are congruent.

We know that corresponding sides of congruent triangles are equal.

Hence

AQ=AV

5x+9=7x+1

9-1=7x-5x

8=2x

divide both sides by 2

4=x

Now plug value of x=4 into UV=7x+1

UV=7*4+1=28+1=29

<u>Hence UV=29 is final answer.</u>

7 0
3 years ago
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