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Lana71 [14]
3 years ago
13

What is the value of x in the expression

Mathematics
1 answer:
kvv77 [185]3 years ago
8 0

Answer:

-12

Step-by-step explanation:

7^{-9} * 7^{-3} = 7^{(-9)+(-3)} = 7^{-12}

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Simplify the expression
Naily [24]

Answer:

6

Step-by-step explanation:

3 sqrt(20) / sqrt(5)

We know that sqrt(a) /sqrt(b) = sqrt(a/b)

3 sqrt(20/5)

3 sqrt(4)

3 *2

6

4 0
3 years ago
Read 2 more answers
Approximate the change in the volume of a sphere when its radius changes from r​ = 40 ft to r equals 40.05 ft (Upper V (r )equal
alexgriva [62]

Answer:

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

Step-by-step explanation:

The volume of the sphere (V), measured in cubic feet, is represented by the following formula:

V = \frac{4\pi}{3}\cdot r^{3}

Where r is the radius of the sphere, measured in feet.

The change in volume is obtained by means of definition of total difference:

\Delta V = \frac{\partial V}{\partial r}\Delta r

The derivative of the volume as a function of radius is:

\frac{\partial V}{\partial r} = 4\pi \cdot r^{2}

Then, the change in volume is expanded:

\Delta V = 4\pi \cdot r^{2}\cdot \Delta r

If r = 40\,ft and \Delta r = 40\,ft-40.05\,ft = 0.05\,ft, the change in the volume of the sphere is approximately:

\Delta V \approx 4\pi\cdot (40\,ft)^{2}\cdot (0.05\,ft)

\Delta V \approx 1005.310\,ft^{3}

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

7 0
3 years ago
There are 6 horses in a race. In how many ways can the first three positions of the order of the finish occur? (Assume there are
timurjin [86]

6\cdot5\cdot4=120

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3 years ago
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42,000 as a multipul of a power of 10
MrRa [10]

Answer:

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Step-by-step explanation:

42000 = 4.2000 \times  \times  {10}^{4}  \\  = 4.2 \times  {10}^{4}

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3 years ago
A line passes through (−1, 5) and (1, 3)
ikadub [295]
I hope this helps you

8 0
3 years ago
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