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Tatiana [17]
4 years ago
11

The graph of a system of equations is shown below.which ordered pair is the best estimate for the solution to the system of equa

tions?
A) (-6,-2)
B) (-3,2)
C) (4,-4)
D) (6,8)

Mathematics
2 answers:
ivanzaharov [21]4 years ago
5 0

Answer:

B. (-3, 2)

Step-by-step explanation:

The solution is given by the coordinates of the point where the lines intersect.

From the graph we see that it is  the point where x = -3 and y = 2.

alisha [4.7K]4 years ago
4 0
The answer is B! Hopes this helps
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1. 2x + 5y = 5

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Step-by-step explanation:

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39.25

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will ran four miles on his first day of training t next day he ran one third that distance how far did he run the second day
andrew11 [14]
<span>(1/3) * 4 = 4/3 = 1 and 1/3 miles</span>
4 0
4 years ago
If sinx = p and cosx = 4, work out the following forms :<br><br><br>​
Kay [80]

Answer:

$\frac{p^2 - 16} {4p^2 + 16} $

Step-by-step explanation:

I will work with radians.

$\frac {\cos^2 \left(\frac{\pi}{2}-x \right)+\sin(-x)-\sin^2 \left(\frac{\pi}{2}-x \right)+\cos \left(\frac{\pi}{2}-x \right)} {[\sin(\pi -x)+\cos(-x)] \cdot [\sin(2\pi +x)\cos(2\pi-x)]}$

First, I will deal with the numerator

$\cos^2 \left(\frac{\pi}{2}-x \right)+\sin(-x)-\sin^2 \left(\frac{\pi}{2}-x \right)+\cos \left(\frac{\pi}{2}-x \right)$

Consider the following trigonometric identities:

$\boxed{\cos\left(\frac{\pi}{2}-x \right)=\sin(x)}$

$\boxed{\sin\left(\frac{\pi}{2}-x \right)=\cos(x)}$

\boxed{\sin(-x)=-\sin(x)}

\boxed{\cos(-x)=\cos(x)}

Therefore, the numerator will be

$\sin^2(x)-\sin(x)-\cos^2(x)+\sin(x) \implies \sin^2(x)- \cos^2(x)$

Once

\sin(x)=p

\cos(x)=4

$\sin^2(x)-\cos^2(x) \implies p^2-4^2 \implies \boxed{p^2-16}$

Now let's deal with the numerator

[\sin(\pi -x)+\cos(-x)] \cdot [\sin(2\pi +x)\cos(2\pi-x)]

Using the sum and difference identities:

\boxed{\sin(a \pm b)=\sin(a) \cos(b) \pm \cos(a)\sin(b)}

\boxed{\cos(a \pm b)=\cos(a) \cos(b) \mp \sin(a)\sin(b)}

\sin(\pi -x) = \sin(x)

\sin(2\pi +x)=\sin(x)

\cos(2\pi-x)=\cos(x)

Therefore,

[\sin(\pi -x)+\cos(-x)] \cdot [\sin(2\pi +x)\cos(2\pi-x)] \implies [\sin(x)+\cos(x)] \cdot [\sin(x)\cos(x)]

\implies [p+4] \cdot [p \cdot 4]=4p^2+16p

The final expression will be

$\frac{p^2 - 16} {4p^2 + 16} $

8 0
3 years ago
How could I find JM ? What is my first move ?
Irina-Kira [14]
Since you didn't answer i think JL is x+26
JK=x+26-x-22=4
KM=19
JM=4+19=23
6 0
3 years ago
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