Answer:
Step-by-step explanation:
Note the ![\sqrt[3]{8}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D)
= 2 and ![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D)
= 5
Thus
![\sqrt[3]{\frac{8}{125} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B8%7D%7B125%7D%20%7D)
= ![\frac{\sqrt[3]{8} }{\sqrt[3]{125} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B8%7D%20%7D%7B%5Csqrt%5B3%5D%7B125%7D%20%7D)
=
Answer:
11
Step-by-step explanation:
So you first start off with 24, then you add 8 cards and take away 12 + 9 cards, making the equation:
24 + 8 - (12 + 9)
= 32 - 21
= 11
Answer:
D) 0 = 2(x + 5)(x + 3)
Step-by-step explanation:
Which of the following quadratic equations has no solution?
We have to solve the Quadratic equation for all the options in other to get a positive value as a solution for x.
A) 0 = −2(x − 5)2 + 3
0 = -2(x - 5) × 5
0 = (-2x + 10) × 5
0 = -10x + 50
10x = 50
x = 50/10
x = 5
Option A has a solution of 5
B) 0 = −2(x − 5)(x + 3)
Take each of the factors and equate them to zero
-2 = 0
= 0
x - 5 = 0
x = 5
x + 3 = 0
x = -3
Option B has a solution by one of its factors as a positive value of 5
C) 0 = 2(x − 5)2 + 3
0 = 2(x - 5) × 5
0 = (2x -10) × 5
0 = 10x -50
-10x = -50
x = -50/-10
x = 5
Option C has a solution of 5
D) 0 = 2(x + 5)(x + 3)
Take each of the factors and equate to zero
0 = 2
= 0
x + 5 = 0
x = -5
x + 3 = 0
x = -3
For option D, all the values of x are 0, or negative values of -5 and -3.
Therefore the Quadratic Equation for option D has no solution.
5/6 and 3/4 don’t have the same denominator so you have to change it to 10/12 and 9/12 to get them to be equivalent then add them together and get 19/12 simplify and get 1 7/12!
