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lesya692 [45]
3 years ago
5

If you have a 5 letters A,B,C,D,E and you can put them in any order how many ways can you place them

Mathematics
1 answer:
IceJOKER [234]3 years ago
4 0

The first letter can be any one of 5.  For each of those . . .
The second letter can be any one of the remaining 4.  For each of those . . .
The third letter can be any one of the remaining 3.  For each of those . . .
The fourth letter can be any one of the remaining 2.  For either of those . . .
The fifth letter is the last remaining one.

  Total number of possibilities = (5 x 4 x 3 x 2 x 1)  = 

                                                          <em> 120 ways</em> to line them up.

Now, may I say that being a hater of school is not something that
makes you cool.  Maybe it does make you one of the crowd, but life
is not a war between you and school.  School is simply something that
a lot of grown-ups spend a lot of money on, and a lot of teachers spend
their whole life on, to make sure that a lot of kids won't go through <em><u>their</u></em>
whole life stupid.  You can learn everything you ever want to know there,
and it's all free.  That's a pretty good deal.

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3x-1

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2 years ago
Macy’s sells 4 TVs for $680. How much would 7 TVs cost?
konstantin123 [22]

First, divide.

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Answer:

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Step-by-step explanation:

4 0
2 years ago
<img src="https://tex.z-dn.net/?f=%28-5x%5E3%29%5E3%2F%2810x%5E5%29%5E2" id="TexFormula1" title="(-5x^3)^3/(10x^5)^2" alt="(-5x^
marta [7]

Answer:

-\frac{5}{4x}

Step-by-step explanation:

<h2>\left(-5x^3\right)^3\div \left(10x^5\right)^2</h2><h2>\frac{-5^3x^9}{\left(10x^5\right)^2}</h2><h2>\frac{-5^3x^9}{10^2x^{10}}</h2><h2>\frac{-5^3x^9}{5^2\cdot \:2^2x^{10}}</h2><h2>\frac{-5x^9}{2^2x^{10}}</h2><h2>\frac{-5}{2^2x}</h2>

-\frac{5}{4x}

- hope it helps! -

<h2 />

3 0
1 year ago
Help please............................
Vesnalui [34]

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csc x / (cot x + tan x)

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1 / [cos x + (sin²x / cos x)]

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