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pickupchik [31]
3 years ago
9

A fish tank, in the shape of a rectangular prism with dimensions 51 cm by 39 cm by 28 cm, is 95% filled with water. A solid log

is placed into the tank, sinks to the bottom, and makes water spill out. The log is shaped like a cylinder with a radius of 5 cm and a height of 44 cm. How much water spills out of the tank?
Mathematics
1 answer:
GenaCL600 [577]3 years ago
6 0

Answer:

The end answer is 669.4

Step-by-step explanation:

So you take the volume of the fish tank: 51*39*28=55692, but the tank is only 95% full, so you take 55692 and divide it by 100 and multiply it by 95, you get 52907.4. Then you calculate the volume of the log: 3.14*5^2*44=3454.

Now that we know these values, we take the volume of the water which is 52907.4 and add the volume of the log 3454 which gets you 56361.4.

Now we know the combined volume of the water and the log, we can remove the volume of the tank, which will still be holding the water that hasn't exceeded the capacity of the tank: 56361.4-55692=669.4

So then we know what has exceeded the capacity of the tank, which is how much water has spilled

So the water spilled equals 669.4 cubic centimetres of water.

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The third term in an arithmetic sequence is 10 and the fifth term is 26.If the first term is a1,which is an equation for the nth
dexar [7]
Just plug in 3 for n and then 5 for n to see if an turns out to be 10 and 26.

n=3:
A) an = 8*3+10 = 34
B) an = 8*3 - 14 = 10  OK
C) an = 16*3+10 = 58
D) an = 16*3 - 38 = 10 OK

n=5:
B) an = 8*5-14 = 26 OK
D) an = 16*5 - 38 = 42

So the answer is B
5 0
3 years ago
The ratio of boys to girls in a volleyball club was 6: 8. There were 36 boys.
SIZIF [17.4K]

Answer:

Might be wrong but 27. Hope this helps

7 0
3 years ago
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The answer is 3/2x but I don’t know how to solve it... please explain
lesya [120]

Answer:

  y = 3/2x by making use of angle relationships in triangles

Step-by-step explanation:

Here's one way to solve it.

  ∠ADE is an external angle to ΔBDE. As such, its measure will be the sum of the measures of the remote interior angles, ∠DBE and ∠DEB:

  ∠ADE = 2x° +y°

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If we call the intersection point of AC and DE point G, then ∠AGE is an exterior angle to ΔADG. As such, its measure is the sum of the remote interior angles:

  ∠AGE = ∠GAD +∠GDA

  3y° = x° +(2x° +y°)

  2y = 3x . . . . . . . . . . subtract y°, collect terms, divide by °

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5 0
4 years ago
3/4x+5/6=5x-125/3 solve for x
vivado [14]
3/4x+5/6=5x-125/3
3/4x+5/6-5/6=5x-125/3-5/6
4/3x=5x-85/2
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(-4*-17/4x)=(-85/2*-4)
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4 0
3 years ago
Noa was walking in the forest and measured the circumference of two trees that he found. The first tree measured 37 5/8 inches a
rodikova [14]

Answer:

Step 4: 44 32/24 - 37 15/24= 8 17/24

<u>Here we can finally find out the mistake done by Noa. The result is 7 17/24 and not 8 17/24.</u>

Step-by-step explanation:

1. Let's review carefully all the steps taken by Noa to calculate the difference of the circumferences of the two trees.

Circumference Tree 1 = 37 5/8 inches around

Circumference Tree 2 =  45 1/3 inches around

Step 1: 45 1/3- 37 5/8

The measures are correct, no issues copying them.

Step 2: 45 8/24 - 37 15/24

Noa looked for common denominators

1/3 * 8/8 = 8 /24 is correct; 5/8 * 3/3 = 15/24 is also correct.

Step 3: 44 32/24 - 37 15/24

Noa looked for making the fraction part higher on the left side:

45 8/24 = 44 32/24 is correct because 24/24 = 1

Step 4: 44 32/24 - 37 15/24= 8 17/24

<u>Here we can finally find out the mistake done by Noa. The result is 7 17/24 and not 8 17/24.</u>

4 0
3 years ago
Read 2 more answers
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