number one is 280 because 4/2 is 2 + 2 is 4 then you multiply 7 and that is 28 ^ 2 which is 280
I believe <span>2 3 5 7 11 13 17 19 23 29 31</span>
The solution to system is x = 0 and y = -1
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
-8x + 2y = -2 ----------- eqn 1
4x + 4y = -4 ---------- eqn 2
We have to solve the system of equations
We can solve the equations by elimination method
<em><u>Multiply eqn 2 by 2</u></em>
8x + 8y = -8 ------ eqn 3
<em><u>Add eqn 1 and eqn 3</u></em>
-8x + 2y = -2
8x + 8y = -8
( + ) ---------------
0x + 2y + 8y = -2 - 8
10y = -10
Divide both sides by 10
y = -1
<em><u>Substitute y = -1 in eqn 1</u></em>
-8x + 2(-1) = -2
-8x - 2 = -2
-8x = -2 + 2
x = 0
Thus the solution to system is x = 0 and y = -1
Answer:
A) x² + 7x - 9
Step-by-step explanation:
Deduct\Add each like-term to arrive at your answer.
Answer:
Step-by-step explanation:
Volumes of two spheres A and B = 648 cm³ and 1029 cm³
Things to remember:
1). Scale factor of two objects =
[
and
are the radii of two circles]
2). Area scale factor = 
3). Volume scale factor = 
Volume scale factor Or Volume ratio = 
![\frac{r_1}{r_2}=\sqrt[3]{\frac{648}{1029} }](https://tex.z-dn.net/?f=%5Cfrac%7Br_1%7D%7Br_2%7D%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B648%7D%7B1029%7D%20%7D)
![\frac{r_1}{r_2}=\frac{6(\sqrt[3]{3})}{7(\sqrt[3]{3})}](https://tex.z-dn.net/?f=%5Cfrac%7Br_1%7D%7Br_2%7D%3D%5Cfrac%7B6%28%5Csqrt%5B3%5D%7B3%7D%29%7D%7B7%28%5Csqrt%5B3%5D%7B3%7D%29%7D)

Therefore, scale factor =
≈ 6 : 7
Area scale factor Or area ratio = 
= 
≈ 36 : 49
Volume scale factor or Volume ratio = 
= 
≈ 216 : 343