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Delvig [45]
3 years ago
9

Henry invested $4,300 in an account paying an interest rate of 3.6% compounded quarterly. Assuming no deposits or withdrawals ar

e made, how long would it take, to the nearest year, for the value of the account to reach $6,730?
Mathematics
1 answer:
lana66690 [7]3 years ago
5 0

Answer:

12.67 years

Step-by-step explanation:

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9x-8y=0<br> Graph the following liner equation
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Y= -9x
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State the various transformations applied to the base function to obtain a graph of the functiong(x) = |x + 1| − 2.
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There were 500 people at a play. the admission price was $6 for general public and $3 for students. the admission receipts were
dem82 [27]
Its 880 i think but hope yhu get it right

5 0
3 years ago
Use quadratic regression to find
vovangra [49]

Answer:

y = 6x² -13x -5

Step-by-step explanation:

(1,-12) (2,-7) (5,80)

y = ax² + bx + c

-12 = a*1² + b*1 + c = a+b+c    (1)

-7 = 4a + 2b + c    (2)

80 = 25a + 5b + c   (3)

(2)-(1): 3a + b = 5    (4)

(3)-(2): 21a + 3b = 87   (5)

(4)*3:     9a + 3b = 15    (6)

(5)-(6):  12a = 72      a = 6

(4)                             b = -13

(2)                             c = -5

4 0
3 years ago
Factor the polynomial, x2 + 5x + 6
patriot [66]

Answer:

Choice b.

x^{2} + 5\, x + 6 = (x + 3)\, (x + 2).

Step-by-step explanation:

The highest power of the variable x in this polynomial is 2. In other words, this polynomial is quadratic.

It is thus possible to apply the quadratic formula to find the "roots" of this polynomial. (A root of a polynomial is a value of the variable that would set the polynomial to 0.)

After finding these roots, it would be possible to factorize this polynomial using the Factor Theorem.

Apply the quadratic formula to find the two roots that would set this quadratic polynomial to 0. The discriminant of this polynomial is (5^{2} - 4 \times 1 \times 6) = 1.

\begin{aligned}x_{1} &= \frac{-5 + \sqrt{1}}{2\times 1} \\ &= \frac{-5 + 1}{2} \\ &= -2\end{aligned}.

Similarly:

\begin{aligned}x_{2} &= \frac{-5 - \sqrt{1}}{2\times 1} \\ &= \frac{-5 - 1}{2} \\ &= -3\end{aligned}.

By the Factor Theorem, if x = x_{0} is a root of a polynomial, then (x - x_0) would be a factor of that polynomial. Note the minus sign between x and x_{0}.

  • The root x = -2 corresponds to the factor (x - (-2)), which simplifies to (x + 2).
  • The root x = -3 corresponds to the factor (x - (-3)), which simplifies to (x + 3).

Verify that (x + 2)\, (x + 3) indeed expands to the original polynomial:

\begin{aligned}& (x + 2)\, (x + 3) \\ =\; & x^{2} + 2\, x + 3\, x + 6 \\ =\; & x^{2} + 5\, x + 6\end{aligned}.

4 0
2 years ago
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