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Ahat [919]
3 years ago
6

Select the correct answer from each drop menu. A functions with the domain {2,3,4} has a specific range. Determine the function

and its range. The function with the domain {2,3,4} is, and it's range is
Domain {2,3,4} is 3x+2 or x+1
range is {2,6,8} or {8,11,14}​
Mathematics
1 answer:
Irina18 [472]3 years ago
3 0

Answer:

2,6.8, the range is 2

Step-by-step explanation:

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liberstina [14]
Third one 
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Ismael made a scaled copy of the following
bixtya [17]

Answer:

Options (A), (B) and (C)

Step-by-step explanation:

In the given figure,

Length of side AD = 16 units

If this side is scaled by a factor = k

Then the length of the corresponding side will be = 16k

If 0 < k < 1,

Then length of the corresponding side will be less than 16.

[Example: If k = \frac{1}{4}

Therefore, scaled side of the corresponding side of the quadrilateral = 16\times \frac{1}{4} = 4]

That means length of corresponding sides may be 4, 6.5 and 12.

Options (A), (B) and (C) will be the answer.

8 0
3 years ago
Factorise 9w² - 100<br><br><br>​
ohaa [14]

Answer:

9\, w^{2} - 100 = (3\, w - 10) \, (3\, w + 10).

Step-by-step explanation:

Fact:

\begin{aligned} & (a - b)\, (a + b)\\ =\; & a^{2} + a\, b - a\, b - b^{2} \\ =\; & a^{2} - b^{2} \end{aligned}.

In other words, (a^{2} - b^{2}), the difference of two squares in the form a^{2} and b^{2}, could be factorized into (a - b)\, (a + b).

In this question, the expression (9\, w^{2} - 100) is the difference between two terms: 9\, w^{2} and 100.

  • 9\, w^{2} is the square of 3\, w. That is: (3\, w)^{2} = 9\, w^{2}.
  • On the other hand, 10^{2} = 100.

Hence:

9\, w^{2} - 100 = (3\, w)^{2} - (10)^{2}.

Apply the fact that a^{2} - b^{2} = (a - b) \, (a + b) to factorize this expression. (In this case, a = 3\, w whereas b = 10.)

\begin{aligned}& 9\, w^{2} - 100 \\ =\; & (3\, w)^{2} - (10)^{2} \\ = \; & (3\, w - 10)\, (3\, w + 10)\end{aligned}.

8 0
3 years ago
B. (4,-7)
zvonat [6]

Answer:

b)-3

c)17

d)-11

Step-by-step explanation:

4,-7)

-3

5 0
3 years ago
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