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e-lub [12.9K]
3 years ago
7

Hey, I WANT A BESTIE PLEASE (imagine I put the lightskin face emoji)

Mathematics
2 answers:
Alex777 [14]3 years ago
4 0

Answer:

heyyy

Step-by-step explanation:

anygoal [31]3 years ago
4 0

Answer:

Heyy

Step-by-step explanation:

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If f(x) = –3x – 5 and g(x) = 4x – 2, find (f – g)(x).
Vikki [24]

Answer:

(f-g)(x)=-7x-3

Step-by-step explanation:

4 0
3 years ago
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The mean age of 3 women in an office is 27 years old.
horrorfan [7]

Answer:

mean age of women

(x+y+z)/3=27

mean age of men

(x1+x2+x3+x4+x5+x6)/6=34

mean age of all people in the office

x+y+z=27*3=81

x1+...x6=34*6=204

so

mean age( x+y+z+x1+x2+..x6)/(3+6)=(27*3+34*6)/9

=(81+204)/9=285/9=32 approximately

4 0
3 years ago
Find the area of the figure below (Do Not put the units in your answer)
Contact [7]

Answer:

54

Step-by-step explanation:

Area of rhombus= (12×9) ÷2

8 0
3 years ago
what should be the rate of interest to earn an 45000 as interest wale rupees 50000 easy in investment for 6 year​
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5

Step-by-step explanation:

6 0
2 years ago
13. Determine whether B = {(-1, 1,-1), (1, 0, 2), (1, 1, 0)} is a basis of R3.
Sholpan [36]

Answer:  Yes, the given set of vectors is a basis of R³.

Step-by-step explanation:  We are given to determine whether the following set of three vectors in R³ is a basis of R³ or not :

B = {(-1, 1,-1), (1, 0, 2), (1, 1, 0)} .

For a set to be a basis of R³, the following two conditions must be fulfilled :

(i) The set should contain three vectors, equal to the dimension of R³

and

(ii) the three vectors must be linearly independent.

The first condition is already fulfilled since we have three vectors in set B.

Now, to check the independence, we will find the determinant formed by theses three vectors as rows.

If the value of the determinant is non zero, then the vectors are linearly independent.

The value of the determinant can be found as follows :

D\\\\\\=\begin{vmatrix} -1& 1 & -1\\ 1 & 0 & 2\\ 1 & 1 & 0\end{vmatrix}\\\\\\=-1(0\times0-2\times1)+1(2\times1-1\times0)-1(1\times1-0\times1)\\\\=(-1)\times(-2)+1\times2-1\times1\\\\=2+2-1\\\\=3\neq 0.

Therefore, the determinant is not equal to 0 and so the given set of vectors is linearly independent.

Thus, the given set is a basis of R³.

5 0
3 years ago
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