Answer:
Step-by-step explanation:
The diagonal ^2= 13^2+7^2
=169+49=218
diagonal = V218
the lengh of the square=l
l^2+l^2= 218
2l^2=218
l^2= 218/2= 109
l= ✓109
Answer:
y = 29
i hope this helped
Step-by-step explanation:
because u have to multiply 4 with 6 since x=6 than add 5 which is 29
Answer: A
Step-by-step explanation:
![y=2x^2-8](https://tex.z-dn.net/?f=y%3D2x%5E2-8)
1. Swap x and y.
![x=2y^2-8](https://tex.z-dn.net/?f=x%3D2y%5E2-8)
2. Solve for the new y.
Add 8
![x+8=2y^2](https://tex.z-dn.net/?f=x%2B8%3D2y%5E2)
Divide by 2.
![\frac{x+8}{2}=y^2](https://tex.z-dn.net/?f=%5Cfrac%7Bx%2B8%7D%7B2%7D%3Dy%5E2)
Extract the square root.
![\sqrt{\frac{x+8}{2} }=y](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7Bx%2B8%7D%7B2%7D%20%7D%3Dy)
Answer:
45°, 63°, 72°
Step-by-step explanation:
The sum of ratio units is 5+7+8=20, so each stands for 180°/20 = 9° of angle. Multiplying the ratio values by 9° gives the angle values:
45° : 63° : 72°
Answer:
Let's define the high temperature as T.
We know that:
"four times T, was more than 2*T plus 66°C"
(i assume that the temperature is in °C)
We can write this inequality as:
4*T > 2*T + 66°C
Now we just need to solve this for T.
subtracting 2*T in both sides, we get:
4*T - 2*T > 2*T + 66°C - 2*T
2*T > 66°C
Now we can divide both sides by 2:
2*T/2 > 66°C/2
T > 33°C
So T was larger than 33°C
Notice that T = 33°C is not a solution of the inequality, then we should use the symbol ( for the set notation.
Then the range of possible temperatures is:
(33°C, ...)
Where we do not have an upper limit, so we could write this as:
(33°C, ∞°C)
(ignoring the fact that ∞°C is something impossible because it means infinite energy, but for the given problem it works)