Answer:
For 32 bits Instruction Format:
OPCODE DR SR1 SR2 Unused bits
a) Minimum number of bits required to represent the OPCODE = 3 bits
There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.
Ceil (log2 (8)) = 3
b) Minimum number of bits For Destination Register(DR) = 4 bits
There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value. 4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.
Ceil (log2 (10)) = 4
c) Maximum number of UNUSED bits in Instruction encoding = 17 bits
Total number of bits used = bits used for registers + bits used for OPCODE
= 12 + 3 = 15
Total number of bits for instruction format = 32
Maximum No. of Unused bits = 32 – 15 = 17 bits
OPCODE DR SR1 SR2 Unused bits
3 bits 4 bits 4 bits 4 bits 17 bits
Answer:
Gland is an organ that makes one or more substances, such as hormones, digestive juices, sweat, tears, saliva, or milk.
TYPES OF GLANDS :
ENDOCRINE glands release the substances directly into the bloodstream.
EXOCRINE glands release the substances into a duct or opening to the inside or outside of the body.
BRAINLIEST PLEASE
The answer is true.
Let's say we are calculating the volume of a grain silo where the the width is a constant, but the height can be changed.
In our code we would calculate the volume using something like:
PI * (WIDTH / 2)^2 * height
The variables in all caps would be named constants. Using them makes the code more readable to other people than if we were to just use their values like:
3.14 * (145.75 / 2)^2 * height
