Answer:  
For 32 bits Instruction Format:
OPCODE   DR               SR1                   SR2      Unused bits
a) Minimum number of bits required to represent the OPCODE = 3 bits
 There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.
Ceil (log2 (8)) = 3
b) Minimum number of bits For Destination Register(DR) = 4 bits
There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value.  4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.  
Ceil (log2 (10)) = 4
c) Maximum number of UNUSED bits in Instruction encoding = 17 bits
Total number of bits used = bits used for registers + bits used for OPCODE  
      = 12 + 3 = 15  
Total  number of bits for instruction format = 32  
Maximum  No. of Unused bits = 32 – 15 = 17 bits  
OPCODE                DR              SR1             SR2              Unused bits
   3 bits              4 bits          4 bits           4 bits                17 bits
 
        
             
        
        
        
Answer:
Gland is an organ that makes one or more substances, such as hormones, digestive juices, sweat, tears, saliva, or milk. 
TYPES OF GLANDS :
ENDOCRINE glands release the substances directly into the bloodstream. 
EXOCRINE glands release the substances into a duct or opening to the inside or outside of the body.
BRAINLIEST PLEASE 
 
        
                    
             
        
        
        
The answer is true. 
Let's say we are calculating the volume of a grain silo where the the width is a constant, but the height can be changed. 
In our code we would calculate the volume using something like:
PI * (WIDTH / 2)^2 * height
The variables in all caps would be named constants. Using them makes the code more readable to other people than if we were to just use their values like:
3.14 * (145.75 / 2)^2 * height