The correct answer for this question is this one: "numerical and financial data." <span>The types of data that you might insert into an Excel workbook to be used in an annual financial statement includes numerical data and financial data."</span>
Hope this helps answer your question and have a nice day ahead.
indeed I think it is correct
The correct answer to the question is Option D (<span>social involvement in technology innovation). It has been said that there are three points at which there must be some social involvement in </span><span>technological innovation:
1. So</span><span>cial need
2. Social resources
3. A sympathetic social ethos
If there is a default in any of these three factors, it is unlikely that a </span>technological innovation will be widely adopted or successful.
Answer:
value=int(input("Enter the number up-to the user wants the Fibonacci series: "))
a=0
b=1
c=1
for x in range(value):
print(c,end=" ")
c=a+b
a=b
b=c
Output :
- If the user input 5, then the output is "1 1 2 3 5".
- If the user input 10, then the output is "1 1 2 3 5 8 13 21 34 55".
Explanation:
- The above defined a python program which is used for the Fibonacci series.
- The first line of the program is used to instruct the user and take the input from the user.
- Then the for loop executes up-to that range value.
- Then in the for-loop, the two variable needs to store the current value and previous value which is used to give the series after addition.
The only way without a while loop and no method I can think of is use switch with every possible variation of the four digit binary which is 15.
Here is the starter code:
import java.util.Scanner;
public class MyClass {
public static void main(String args[]) {
Scanner sc = new Scanner(System.in);
int digit = sc.nextInt();
switch(digit) {
case 0000:
System.out.println("0");
break;
case 0001:
System.out.println("1");
break;
case 0010:
System.out.println("2");
break;
case 0011:
System.out.println("3");
break;
case 0100:
System.out.println("4");
break;
… (fill in other cases)
}
}
}
Use this link: https://www.electronics-tutorials.ws/binary/bin_3.html
There might be a better way, but without loops or methods this is all I got.
