3 years ago

Simplify (a^3b^12c^2)(a^5c^2)(b^5c^4)^0

1 answer:

4 0

Your answer should be a^8b^12c^4
Hope this helps!

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QveST [7]

Factors of 4: 2 and 2
y= (x+2)²
+√y or -√y = x+2

x= 2+√y , 2-√y

interchange variables
y= 2+√x , 2-√x

f ⁻¹(x) = 2 + √x, 2 - √x

8 0

3 years ago

statuscvo [17]

the answe is a- n>13

4 0

4 years ago

o-na [289]

I think it is 1/2
hope this helped

8 0

3 years ago

s2008m [1.1K]

Answer:

$x^3-8x^2+5x+14$

Step-by-step explanation:

We have been given the zeroes of polynomial which are -1,2,7

That means the factors are (x+1) (x-2) (x-7)

When we want to a polynomial from zeroes we multiply the factors

$(x+1)(x-2)(x-7)$

$(x+1)(x^2-7x-2x+14)$

$(x+1)(x^2-9x+14)$

$(x^3-9x^2+14x+x^2-9x+14$

$x^3-8x^2+5x+14$

Hence, the required polynomial is:

$x^3-8x^2+5x+14$

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3 years ago

kirill [66]

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3 years ago