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stepladder [879]
3 years ago
6

ILUUN, Tha his profit per cent.

Mathematics
1 answer:
sveta [45]3 years ago
7 0

Answer:

listen to me dont tell this no body ok

Step-by-step explanation:

i have pwer ANSWER is 2

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Chiara has 26 coins that equal 34 cents. All the coins are pennies, p, and nickels, n. How many nickels and pennies does Chiara
wlad13 [49]

Answer:

Chiara has 2 penny coins and 24 nickel coins

Step-by-step explanation:

Let

p ----> the number of penny coins

n ---> the number of nickel coins

Remember that

1\ penny=\$0.01

1\ nickel=\$0.05

Chiara has 26 coins that equal 34 cents

so

p+n=26

isolate the variable x

p=26-n ----> equation A

34 cents=$0.34

0.01p+0.05n=0.34

Multiply by 100 both sides

p+5n=34

isolate the variable x

p=34-5n -----> equation B

Create a table  to guess

assume  different values of n and determine the value of p in equation A and equation B

The solution is when the value of p in the equation A must be equal to the value of p in equation B

1) For n=1

equation A

p=26-1=25

equation B

p=34-5(1)=29

29\neq 25

2) For n=2

equation A

p=26-2=24

equation B

p=34-5(2)=24\\24=24

therefore

The solution is (2,24)

Chiara has 2 penny coins and 24 nickel coins

3 0
3 years ago
Read 2 more answers
What is the area of the trapezoid below?
goldenfox [79]

Answer:

Area 684 m squared

Step-by-step explanation:

26 + 46 = 72

72/2 = 36

36 x 19 = 684

Hope this helps!

5 0
3 years ago
Please help me thank you
kicyunya [14]
Answer is -1/2 or -0.5

3 0
3 years ago
Read 2 more answers
Can someone help me (7th grade science) need to be done as soon as possible
tangare [24]

Answer:

oouu I'm in 7th grade science and I already did this I can help!

3 0
3 years ago
Which recursive definition could be used to generate the sequence {1, 2,2,4,8,32}
Alexandra [31]
Given that the sequence is:
1,2,4,8,32
the recursive formula will be found as follows:
first term is=1
the sequence can be written as:
1,2,4,8,32
=(1*2^0),(1*2^1),(1*2^2),(1*2^3),(1*2^4)
thus the recursive formula will be
an=a1(r)^(n-1)
plugging the values we get:
an=1(2)^(n-1)
5 0
3 years ago
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