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umka2103 [35]
3 years ago
9

What is in between 0.08 & 0.4

Mathematics
1 answer:
Margarita [4]3 years ago
5 0
There are a lot of numbers between 0.08 and 0.4 
such as 0.09,0.1,0.11,0.12,0.13 etc.
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each pail of plaster covers 90 square feet of ceiling. What is the least number of pails of plaster you would need to buy to cov
Dominik [7]
The area of the ceiling:
 A = 14² = 196 ft²
 We need plaster to cover 196 ft².
 196 : 90 = 2.17778
 Answer:  We have to buy 3 pails of plaster.
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3 years ago
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a boat traveled 14 miles per hour downstream. the trip upstream was at a speed of 10 miles per hour. what is the speed of the bo
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Answer:

(im not sure what the first question is asking me)

Speed of the current is 2 miles per hour

Step-by-step explanation:

The reason the current is 2 miles per hour is because it when going down stream they were going 14 miles per hour, going upstream they went 10. The difference is 4mph. So if the current pushes you 2mph when going down stream and holds you 2 mph when going up, the constant speed is 12mph then you add and subtract 2 becuase of the two directions youre traveling. hence 10mph and 14mph.

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A tortoise is walking in the desert. It walks for 17.92 meters at a speed of 7 meters per minute. For how many minutes does it w
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Which of the following shows the polynomial below written in descending
liraira [26]

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C.

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1. The number of rabbits on an island is increasing exponentially.
Zina [86]

Answer:

<em>There are approximately 114 rabbits in the year 10</em>

Step-by-step explanation:

<u>Exponential Growth </u>

The natural growth of some magnitudes can be modeled by the equation:

P=P_o(1+r)^t

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.

We are given two measurements of the population of rabbits on an island.

In year 1, there are 50 rabbits. This is the point (1,50)

In year 5, there are 72 rabbits. This is the point (5,72)

Substituting in the general model, we have:

50=P_o(1+r)^1

50=P_o(1+r)\qquad\qquad[1]

72=P_o(1+r)^5\qquad\qquad[2]

Dividing [2] by [1]:

\displaystyle \frac{72}{50}=(1+r)^{5-1}=(1+r)^{4}

Solving for r:

\displaystyle r=\sqrt[4]{\frac{72}{50}}-1

Calculating:

r=0.095445

From [1], solve for Po:

\displaystyle P_o=\frac{72}{(1+r)^5}

\displaystyle P_o=\frac{72}{(1.095445)^5}

P_o=45.64355

The model can be written now as:

P=45.64355(1.095445)^t

In year t=10, the population of rabbits is:

P=45.64355(1.095445)^{10}

P = 113.6

P\approx 114

There are approximately 114 rabbits in the year 10

5 0
3 years ago
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