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umka2103 [35]
3 years ago
9

What is in between 0.08 & 0.4

Mathematics
1 answer:
Margarita [4]3 years ago
5 0
There are a lot of numbers between 0.08 and 0.4 
such as 0.09,0.1,0.11,0.12,0.13 etc.
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The perimeter of a college basketball court is 96 meters and the length is 14 meters more than the width. What are the dimension
soldi70 [24.7K]

Answer:

length = 32m, width= 16m

Step-by-step explanation:

l=2w

2(2w+w)=96

2(3w)=96

6w=96,w= 96/6 = 16m

l=2w=2x16=32m

8 0
3 years ago
Read 2 more answers
Please please help me please
nydimaria [60]

The area of a circle is

A=\pi r^2

The radius is half the diameter, so we have

A=\pi \left(\dfrac{11}{2}\right)^2

5 0
3 years ago
What is the surface area of a piece of pipe that is open at both ends, has a radius of 6 inches, and a height of 18 inches? (Use
elena-14-01-66 [18.8K]
<span> it's 2x3.14 times 6 times 18

</span><span>2π(6)(18)</span>
6 0
4 years ago
Read 2 more answers
Parallelogram MNPQ was dilated to create parallelogram M'N'P'Q'. On a coordinate plane, 2 parallelograms are shown. Parallelogra
Naddika [18.5K]

Answer:

The answer is below

Step-by-step explanation:

Which statements are true about the parallelograms? Check all that apply.

The length of side MN is 2 units.

The length of side M'N' is 5 units.

The image is smaller than the pre-image.

Sides MQ and M'Q' both have the same slope, 1.

The scale factor is 2/5

a) The length of side MN is determined using the formula:

|MN|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(4-2)^2+(-2-(-2))^2}=\sqrt{2^2}=2\\  \\ |MN|=2

The first option is correct

b) The length of side M'N' is determined using the formula:

|M'N'|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(10-5)^2+(-5-(-5))^2}=\sqrt{5^2}=2\\  \\ |M'N'|=5

The second option is correct

c) From the coordinates of parallelogram MNPQ and M'N'P'Q', we can see that parallelogram MNPQ is dilated by a factor of 5/2 to produce parallelogram M'N'P'Q' , hence parallelogram M'N'P'Q'  is bigger that parallelogram MNPQ. This means that The image is bigger than the pre-image.

The third option is wrong

d) The slopes are given as:

Slope\ of\ MQ=\frac{Change\ in\ y}{Change\ in\ x}=\frac{1-2}{-3-(-2)} =1\\ \\Slope\ of\ M'Q'=\frac{Change\ in\ y}{Change\ in\ x}=\frac{3-5}{-7-(-5)} =1\\

Option four is correct

e) From the coordinates of parallelogram MNPQ and M'N'P'Q', we can see that parallelogram MNPQ is dilated by a factor of 5/2 to produce parallelogram M'N'P'Q', hence the scale factor is 5/2

Option 5 is wrong

6 0
3 years ago
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6) -5x - 7y= 11<br> x - 2y=-9
sladkih [1.3K]

Answer:

Please check the attachment.

HOPE U UNDERSTOOD

COMMENT IF ANY DOUBTS

THANK YOU.

3 0
4 years ago
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