Ask question

Ask question

All categories

2 years ago

9

What is in between 0.08 & 0.4

1 answer:

Margarita [4]2 years ago

5 0

There are a lot of numbers between 0.08 and 0.4
such as 0.09,0.1,0.11,0.12,0.13 etc.

You might be interested in

30 points + brainliest answer.<br> Answer D got cut off, it is 5/18.

Basile [38]

C. 5/6

30 people with soda + 45 people with lemonade = 75/90 people

simplifies to 5/6.

3 0

3 years ago

For a ride on a rental scooter, John paid an $8 fee to start the scooter plus 6 cents per minute of the ride. The total bill for

enot [183]

The linear equation is $8+0.06x=19.94$ and John rode the scooter for $199$ minutes.

Fee to start the scooter $=$ $ $8$ .

Fee to ride per minute $= 6$ cents $=$ $ $0.06$ .

Total bill $=$ $ $19.94$ .

Let $x$ be the minutes for which he rides the scooter.

The linear equation is formed as:

$8+0.06x=19.94$

$0.06x=19.94-8$

$0.06x=11.94$

$x=199$ minutes.

So, John rode the scooter for $199$ minutes.

Learn more about linear equation here:

brainly.com/question/24794429?referrer=searchResults

5 0

1 year ago

Read 2 more answers

The line passes through (2,1) and (6,7)

Ilya [14]

............y=3/2x-2

3 0

2 years ago

How do you solve d+12=2 using mental math

n200080 [17]

By minusing 12 to both sides
d+12=2
-12=-12
d =-10

5 0

3 years ago

Find the area each sector. Do Not round. Part 1. NO LINKS!!<br><br>

sladkih [1.3K]

Answer:

$\textsf{Area of a sector (angle in degrees)}=\dfrac{\theta}{360 \textdegree}\pi r^2$

$\textsf{Area of a sector (angle in radians)}=\dfrac12r^2\theta$

17) Given:

$\theta$ = 240°
r = 16 ft

$\textsf{Area of a sector}=\dfrac{240}{360}\pi \cdot 16^2=\dfrac{512}{3}\pi \textsf{ ft}^2$

19) Given:

$\theta=\dfrac{3 \pi}{2}$
r = 14 cm

$\textsf{Area of a sector}=\dfrac12\cdot14^2 \cdot \dfrac{3\pi}{2}=147 \pi \textsf{ cm}^2$

21) Given:

$\theta=\dfrac{ \pi}{2}$
r = 10 mi

$\textsf{Area of a sector}=\dfrac12\cdot10^2 \cdot \dfrac{\pi}{2}=25 \pi \textsf{ mi}^2$

23) Given:

$\theta$ = 60°
r = 7 km

$\textsf{Area of a sector}=\dfrac{60}{360}\pi \cdot 7^2=\dfrac{49}{6}\pi \textsf{ km}^2$

3 0

2 years ago