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3 years ago

Please help me remember how to solve this equation: (13+x)².

Mathematics

1 answer:

Sergeeva-Olga [200]3 years ago

7 0

Answer:

x²+26x+169

Step-by-step explanation:

Factor it out:

1) (x+13) (x+13)

2) Distributive property:

x²+13x+13x+169 or x²+26x+169

Hope this helps!! :D

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Find the solution of 3 times the square root of the quantity of x plus 6 equals negative 12, and determine if it is an extraneou

Anna35 [415]

For this case we have the following equation:
$3 \sqrt{x+6}=-12$
Rewriting we have:
$\sqrt{x+6}= \frac{-12}{3}$
$\sqrt{x+6}=-4$
We raise both members of the equation to the square:
$(\sqrt{x+6})^2=(-4)^2$
Rewriting we have:
$x+6=16$
$x=16-6$
$x=10$
It's a extraneous solution because equality is not met by substituting x = 10 in the original equation:
$3 \sqrt{10+6}=-12$
$3 \sqrt{16}=-12$
$3(4)=-12$
$12=-12$
Answer:
The solution is:
$x=10$
It's a extraneous solution

6 0

3 years ago

13 + 31 = 24 not 44 how on earth is this possible all help is great. Thanks.

Aneli [31]

It is 44. Can't argue about that

3 0

3 years ago

If X²⁰¹³ + 1/X²⁰¹³ = 2, then find the value of X²⁰²² + 1/X²⁰²² = ?

enyata [817]

Step-by-step explanation:

$\bf➤ \underline{Given-} \\$

$\sf{x^{2013} + \frac{1}{x^{2013}} = 2}\\$

$\bf➤ \underline{To\: find-} \\$

$\sf {the\: value \: of \: x^{2022} + \frac{1}{x^{2022}}= ?}\\$

$\bf ➤\underline{Solution-} \\$

Let us assume that:

$\rm: \longmapsto u = {x}^{2013}$

Therefore, the equation becomes:

$\rm: \longmapsto u + \dfrac{1}{u} = 2$

$\rm: \longmapsto \dfrac{ {u}^{2} + 1}{u} = 2$

$\rm: \longmapsto{u}^{2} + 1 = 2u$

$\rm: \longmapsto{u}^{2} - 2u + 1 =0$

$\rm: \longmapsto {(u - 1)}^{2} =0$

$\rm: \longmapsto u = 1$

Now substitute the value of u. We get:

$\rm: \longmapsto {x}^{2013} = 1$

$\rm: \longmapsto x = 1$

Therefore:

$\rm: \longmapsto {x}^{2022} + \dfrac{1}{ {x}^{2022} } = 1 + 1$

$\rm: \longmapsto {x}^{2022} + \dfrac{1}{ {x}^{2022} } = 2$

★ Which is our required answer.

$\textsf{\large{\underline{More To Know}:}}$

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)³ = a³ + 3ab(a + b) + b³

(a - b)³ = a³ - 3ab(a - b) - b³

a³ + b³ = (a + b)(a² - ab + b²)

a³ - b³ = (a - b)(a² + ab + b²)

(x + a)(x + b) = x² + (a + b)x + ab

(x + a)(x - b) = x² + (a - b)x - ab

(x - a)(x + b) = x² - (a - b)x - ab

(x - a)(x - b) = x² - (a + b)x + ab

6 0

3 years ago

Find the value of a² + b² , when a+ b = 8 and ab = 12

mezya [45]

Answer:

Step-by-step explanation:

6+2=8

6*2=12

$6^{2}$ + $2^{2}$ = 36+4=40

4 0

2 years ago

Read 2 more answers

Write the expression in standard form. five divided by quantity three minus fifteen i.

EleoNora [17]

Standard form is a+bi where a and b are real numbers
remeber that i²=-1

ok

$\frac{5}{3-15i}$
we got to get the i out of the denomenator
remember the differnce of 2 perfect squares where (a-b)(a+b)=a²-b²

so multiply the whole thing by $\frac{3+15i}{3+15i}$
we get
$\frac{5(3+15i)}{3^2-(15i)^2}=\frac{15+75i}{9-225(-1)}=\frac{15+75i}{9+225}=$ $\frac{15+75i}{234}=\frac{15}{234}+\frac{75i}{234}=\frac{15}{234}+\frac{75}{234}i=\frac{5}{78}+\frac{25}{78}i$

in standard form, it is $\frac{5}{78}+\frac{25}{78}i$

5 0

3 years ago