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Arte-miy333 [17]
3 years ago
14

Please help me remember how to solve this equation: (13+x)².

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
7 0

Answer:

x²+26x+169

Step-by-step explanation:

Factor it out:

1)           (x+13) (x+13)


2) Distributive property:

        x²+13x+13x+169 or x²+26x+169


Hope this helps!! :D

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New equation: 4c+2 2/3+ (-8c) + 5
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Read 2 more answers
The joint probability mass function of XX and YY is given by p(1,1)=0p(2,1)=0.1p(3,1)=0.05p(1,2)=0.05p(2,2)=0.3p(3,2)=0.1p(1,3)=
inessss [21]

Answer:

P(Y=1|X=3)=0.125

Step-by-step explanation:

Given :

p(1,1)=0  

p(2,1)=0.1

p(3,1)=0.05

p(1,2)=0.05

p(2,2)=0.3

p(3,2)=0.1

p(1,3)=0.05

p(2,3)=0.1

p(3,3)=0.25

Now we are supposed to find the conditional mass function of Y given X=3 :  P(Y=1|X=3)

P(X=3) = P(X=3,Y=1)+P(X=3,Y=2) +P(X=3,Y=3)

P(X=3)=p(3,1) +p(3,2) +p(3,3)

P(X=3)=0.05+0.1+0.25=0.4

P(Y=1|X=3)=\frac{P(X=3,Y=1)}{P(X=3)} =\frac{p(3,1)}{P(X=3)}=\frac{0.05}{0.4}= 0.125

Hence P(Y=1|X=3)=0.125

8 0
3 years ago
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