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Arte-miy333 [17]
3 years ago
14

Please help me remember how to solve this equation: (13+x)².

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
7 0

Answer:

x²+26x+169

Step-by-step explanation:

Factor it out:

1)           (x+13) (x+13)


2) Distributive property:

        x²+13x+13x+169 or x²+26x+169


Hope this helps!! :D

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Answer:

3<em>x </em>+ 2<em>y</em> = 34. and two possible pairs of positive numbers are  (<em>x</em>, <em>y</em>) = (10, 2) and (<em>x</em>, <em>y</em>) = (4, 11).

Step-by-step explanation:

 Let the First positive number be <em>x</em> and second positive number be <em>y.</em>

Triple of first number = 3<em>x</em>

double of second number = 2<em>y</em>

According to question,

3<em>x </em>+ 2<em>y</em> = 34

Therefore, the equation is 3<em>x </em>+ 2<em>y</em> = 34

So the two possible pair of numbers Diego would be thinking of must satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34

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Let x = 10 and by substituting its value in above expression,

3 \times 10 = 34 - 2y

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y = 2

Therefore first pair (<em>x</em>, <em>y</em>) = (10, 2)

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3<em>x </em>= 34 - 2<em>y</em>

3 \times 4 = 34 - 2y

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y = 11

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Therefore, (<em>x</em>, <em>y</em>) = (4, 11) and  (<em>x</em>, <em>y</em>) = (10, 2) are the two possible pairs of numbers Diego could be thinking of as these both values satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34.  

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