Two parallel lines are crossed by a transversal.What is the value of k?
2 answers:
Answer:
<h2>k = 60</h2>Step-by-step explanation:
<em>The complete problem is attached.</em>
From the interception of two parallels lines and a transversal, results 8 angles, which are related, there are certain pair of angles that are congruent. We have alternate angles, which can be exterior or interior, we have corresponding angles, and vertical angles, all of those pairs are always congruent.
In the graph, we see that the given angles are alternate exterior angles, which always are congruent. So, we can equalize that pair and solve the equation for <em>k:</em>
<em></em>
Therefore the value of <em>k </em>is 60. The correct answer is the third one.
(Pay attention on the definition we used, just basing on alternate angles we could find a relation to find <em>k</em>, in most of the cases you solve geometric problems like that, looking for the ways to find a relation that allow you to answer the question).
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Answer:
A = 57.97 cm²
Step-by-step explanation:
The area (A) of a trapezium is calculated as
A = h (a + b)
where h is the perpendicular height and a, b the parallel bases
Here h = 6.2, a = 10.8 and b = 7.9, thus
A = × 6.2 × (10.8 + 7.9) = 3.1 × 18.7 = 57.97 cm²
The solution is the point of intersection between the two equations.
Assuming you have a graphing calculator or a program to lets you graph equations (I use desmos) you simply put in the equetions and note down the coordinates of the point of intersection.
In the graph the first equation is in blue and the second in red.
The point of intersection = the solution = (-6 , -1)
If you dont have access to a graphing calculator you could draw the graphs by hand;
1) Draw a table of values for each equation; you do this by setting three or four values for x and calculating its image in y (you can use any values of x)
y = 0.5 x + 2 (Im writing 0.5 instead of 1/2 because I find its easier in this format)
x | y
-1 | 1.5 * y = 0.5 (-1) + 2 = 1.5
0 | 2 * y = 0.5 (0) + 2 = 2
1 | 2.5 * y = 0.5 (1) + 2 = 2.5
2 | 3 * y = 0.5 (2) + 2 = 3
y = x + 5
x | y
-1 | 4 * y = (-1) + 5 = 4
0 | 5 * y = (0) + 5 = 5
1 | 6 * y = (1) + 5 = 6
2 | 7 * y = (2) + 5 = 7
2) Plot these point on the graph
I suggest to use diffrent colored points or diffrent kinds of point markers (an x or a dot) to avoid confusion about which point belongs to which graph
3) Using a ruler draw a line connection all the dots of one graph and do the same for the other
4) The point of intersection is the solution
Assuming you have a graphing calculator or a program to lets you graph equations (I use desmos) you simply put in the equetions and note down the coordinates of the point of intersection.
In the graph the first equation is in blue and the second in red.
The point of intersection = the solution = (-6 , -1)
If you dont have access to a graphing calculator you could draw the graphs by hand;
1) Draw a table of values for each equation; you do this by setting three or four values for x and calculating its image in y (you can use any values of x)
y = 0.5 x + 2 (Im writing 0.5 instead of 1/2 because I find its easier in this format)
x | y
-1 | 1.5 * y = 0.5 (-1) + 2 = 1.5
0 | 2 * y = 0.5 (0) + 2 = 2
1 | 2.5 * y = 0.5 (1) + 2 = 2.5
2 | 3 * y = 0.5 (2) + 2 = 3
y = x + 5
x | y
-1 | 4 * y = (-1) + 5 = 4
0 | 5 * y = (0) + 5 = 5
1 | 6 * y = (1) + 5 = 6
2 | 7 * y = (2) + 5 = 7
2) Plot these point on the graph
I suggest to use diffrent colored points or diffrent kinds of point markers (an x or a dot) to avoid confusion about which point belongs to which graph
3) Using a ruler draw a line connection all the dots of one graph and do the same for the other
4) The point of intersection is the solution