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2 years ago

10

How many times can 144 go into 2873

1 answer:

Reika [66]2 years ago

7 0

19.95 times so pretty much 19

You might be interested in

Stella [2.4K]

Answer:

The first one is d: x=0 or x=6

the second one is the 3rd one

Step-by-step explanation:

8 0

2 years ago

Reva is playing a bean-bag toss game. For each bag that misses the board, the player scores 8 points. Reva misses the board 4 ti

chubhunter [2.5K]

Answer:

a. -32

Step-by-step explanation:

5 0

2 years ago

In right triangle DEF, ∠E is a right angle, m∠D=26∘, and DF=4.5.

jok3333 [9.3K]

Answer:

The measurement of EF is 1.98 units

Step-by-step explanation:

In Δ DEF

∵ m∠E = 90°

∴ FD is the hypotenuse of the triangle

∵ m∠D = 26°

∵ EF is opposite to angle D

- We can use the sine ratio to find it

∵ sin D = $\frac{EF}{FD}$ ⇒ (opposite side / hypotenuse)

∵ FD = 4.5 units

∴ sin(26) = $\frac{EF}{4.5}$

- Multiply both sides by 4.5

∴ 4.5 sin(26) = EF

∵ sin 26° ≈ 0.44

∴ 4.5(0.44) = EF

∴ 1.98 = EF

The measurement of EF is 1.98 units

3 0

2 years ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago

Suppose y varies directly as x, and y =15 when x = 3. Find the constant of variation (k).

vovangra [49]

Answer:

k = 5

Step-by-step explanation:

y = kx

15 = k(3)

k = 15/3

k = 5

8 0

2 years ago