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Jlenok [28]
3 years ago
12

Given f(x)=x3 and g(x)= 1-5x2, fine (fog)(x) and it’s Domain

Mathematics
2 answers:
Yuri [45]3 years ago
6 0

Answer:

The correct choice is B

Step-by-step explanation:

The composite function (f o g)(x) is evaluated by substituting g(x) in place of x in f(x) which yields; (f o g)(x) = (g(x))^3 which finally becomes; (1-5x^2)^3. This function clearly is not a rational function and as such it has no undefined points nor domain constraints. It is defined and real for every value of x.

andre [41]3 years ago
5 0

Answer:

Option B. f(g(x)) = (1-5x ^ 2) ^ 3  all real numbers

Step-by-step explanation:

We have

f(x) = x ^ 3 and g(x) = 1-5x ^ 2

They ask us to find

(fog)(x) and it's Domain

To solve this problem we must introduce the function g(x) within the function f(x)

That is, we must do f(g(x)).

So, we have:

f(x) = x ^ 3

g(x) = 1-5x ^ 2

Then:

f(g(x)) = (1-5x ^ 2) ^ 3

The domain of the function f(g(x)) is the range of the function g(x) = 1-5x ^ 2.

Since the domain and range of g(x) are all real numbers then the domain of f(g(x)) are all real numbers

Therefore the correct answer is the option b: f(g(x)) = (1-5x ^ 2) ^ 3

And his domain is all real.

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Betty has some hair ribbons that are blue. She has 19 blue ribbons. Three times the number of blue ribbons decreased by 5 is gre
likoan [24]

Answer:

3x-5> 6x- 14

Step-by-step explanation:

Let the blue ribbons be denoted by the letter x.

Then according to the given condition

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is greater than

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Putting in one line

3x-5> 6x- 14

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3x-5> 6x- 14

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Now putting the values for x= 3

3x-5> 6x- 14

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4>4  False

Now putting the values for x= 2

3x-5> 6x- 14

6-5> 12-14

1> -2   True

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