PLEASE HELP! MATH

Mathematics

2 answers:

nikdorinn [45]3 years ago

5 0

6x^4+9x^2+12x/3x = 2x^3+3x+4

So the answer is D. 2x3 + 3x + 4

Usimov [2.4K]3 years ago

3 0

Answer:

D) $2x^{3} +3x + 4$ .

Step-by-step explanation:

Given : quantity 6 times x to the 4th power plus 9 times x to the 2nd power plus 12 times x all over 3 times x.

To find : Simplify completely the quantity.

Solution : We have given that a statement .

According to question:

6 times x to the 4th power = $6x^{4}$ .

9 times x to the 2nd power = $9x^{2}$ .

12 times x = 12x.

$6x^{4}$ + $9x^{2}$ + 12x over 3x.

$\frac{6x^{4}}{3x} +\frac{9x^{2}}{3x} +\frac{12x}{3x}$ .

On dividing we get ,

$2x^{3} +3x + 4$ .

Therefore, D) $2x^{3} +3x + 4$ .

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N 1968, it cost $54,000 for a 30-second commercial during the Super Bowl. In 1973, the cost for a 30-second commercial was $88,0

Yuri [45]

Answer:

In 5 years, the price increased about 30%.

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6 0

3 years ago

Plz help me with this

AnnZ [28]

Answer: $\bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}$

Step-by-step explanation:

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, $B=\dfrac{6}{5}$ → $P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}$

Half of that period is: $\dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}$

Calculate the period for each of the options to find a match:

$A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}$