The quotient of a number divided by 8 decreased by 5 is equal to 15.

You graph the function f(x)=-|×|-12

Firlakuza [10]

Answer:

See attachment

Step-by-step explanation:

We want to graph $f(x)=|x|-12$ on the interval -10 to 10.

Let $g(x)=|x|$ be the parent absolute value function.

We can easily graph $f(x)=|x|-12$ , if we use translation.

When the parent function is shifted downwards by 12 units, we obtain the graph of $f(x)=|x|-12$ .

The parent function is a v-shaped graph with vertex at the origin.

We shift the parent function down so that its vertex is now at (0,-12) to get the graph of $f(x)=|x|-12$ .

See attachment for the graph of $f(x)=|x|-12$ on the specified interval.

7 0

3 years ago

Read 2 more answers

The value of x is Helllpp

rewona [7]

a.84

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lemme know if u need explanation

6 0

3 years ago

Read 2 more answers

The drama club spent $35 on decorations and $8.50 per person on food for a cast party. The total cost of the food

jenyasd209 [6]

Answer:

Option C) 27 people

Step-by-step explanation:

Let

x ----> the number of people

we know that

The cost of decorations ($35) plus the number of people (x) multiplied by the cost per person on food ($8.50) must be equal to $264.50

so

The linear equation that represent this situation is

$35+8.50x=264.50$

solve for x

Subtract 35 both sides

$8.50x=264.50-35$

$8.50x=229.50$

Divide by 8.50 both sides

$x=229.50/8.50$

$x=27\ people$

5 0

3 years ago

The circumstances of a circle is 15 π centimeters. What is the area of the circle in terms of π?

zalisa [80]

Answer:

17.90493 is the area

Step-by-step explanation:

8 0

3 years ago

A taxi driver provides service in two zones of a city. Fares picked up in zone A will have destinations in zone A with a probabi

sammy [17]

Answer:

The taxi driver's average profit per trip is 4.4.

Step-by-step explanation:

Probability of fares picked up in zone A with destinations in zone A = 0.6

Probability of fares picked up in zone A with destinations in zone B = 0.4

Probability of fares picked up in zone B with destinations in zone A = 0.3

Probability of fares picked up in zone B with destinations in zone B = 0.7

The driver's expected profit for a trip entirely in zone A = 6

The driver's expected profit for a trip entirely in zone B = 8

The driver's expected profit for a trip involving both zones is 12

The taxi driver's average profit per trip:

zone A with destinations in zone A = 0.6 * 6 = 3.6

zone A with destinations in zone B = 0.4 * 12 = 4.8

zone B with destinations in zone A = 0.3 * 12 = 3.6

zone B with destinations in zone B = 0.7 * 8 = 5.6

Total profit expected for 4 trips = 17.6

Average profit per trip = 4.4 (17.6/4)

7 0

3 years ago