All categories

3 years ago

What's x and y for x=1+y and 2y+x=10

2 answers:

8 0

Substitute the value of x in equation 2. Then you'll get y=3. Then again substitute the value of y in x=1+y, you'll get x=4

Andrew [12]3 years ago

8 0

Y=3,x=4
You plug in 1+y for x in the other equation so it becomes 2y+1+y=10
Then, you combine the 2y and y to make 3y so its 3y+1=10
Then, move the 1 over so you get 3y=10-1 which makes 3y=9
Then, divide the 3 and you end up with y=3

To find x
plug y back into the ORIGINAL formula x=1+y OR 2y+x=10
assuming u used x=1+y you would get x=1+3
which gives you x=4

You might be interested in

There are 10 girls and 8 boys in Mr Augellis class. If 5 more girls and 5 more boys join the class, will the ratio of girls to b

zimovet [89]

Yes they will stay the same

8 0

3 years ago

Which value of a would make the expression 5 1/3 divided by 4/a equivalent to a whole number?

Leya [2.2K]

9514 1404 393

Answer:

a = any positive multiple of 3

Step-by-step explanation:

You want ...

(5 1/3)/(4/a) = whole number

(16/3)·(a/4) = whole number

(4a/3) = whole number

This will be the case for a = 3n, for any positive integer n.

8 0

3 years ago

What is the result of 96 divided by 6?8 12 16 or 32

hram777 [196]

96 divided by 6 is 16

96 divided by 8 is 12

96 divided by 12 is 8

96 divided by 16 is 6

96 divided by 32 is 3

8 0

3 years ago

Read 2 more answers

Write an expression for the 12th partial sum of the series 3/2+7/3+19/6+... using summation notation

lapo4ka [179]

Answer:

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=73$

Step-by-step explanation:

$First\ term\ of\ the\ series(a_1)=\frac{3}{2}\\\\Second\ term\ of\ the\ series(a_2)=\frac{7}{3}\\\\Third\ term\ of\ the\ series(a_3)=\frac{19}{6}\\\\a_2-a_1=\frac{7}{3}-\frac{3}{2}=\frac{5}{6}\\\\a_3-a_2=\frac{19}{6}-\frac{7}{3}=\frac{5}{6}\\\\Hence\ it\ is\ an\ Arithmetic\ Series\ with\ first\ term=\frac{3}{2}\ and\ constant\ difference=\frac{5}{6}$

$a_1=\frac{3}{2}+0\times \frac{5}{6}\\\\a_2=\frac{3}{2}+1\times \frac{5}{6}\\\\a_3=\frac{3}{2}+2\times \frac{5}{6}\\\\.\\.\\.\\a_n=\frac{3}{2}+(n-1)\times \frac{5}{6}\\\\S_n=a_1+a_2+a_3+......+a_n\\\\S_n=(\frac{3}{2}+0\times \frac{5}{6})+(\frac{3}{2}+1\times \frac{5}{6})+(\frac{3}{2}+2\times \frac{5}{6})+....+(\frac{3}{2}+[n-1]\times \frac{5}{6})\\\\S_n=\sum_{i=1}^n [\frac{3}{2}+(i-1)\times \frac{5}{6}]\\\\S_n=(\frac{3}{2}+\frac{3}{2}+\frac{3}{2}+...n\ times)+\frac{5}{6}(1+2+3+4+...+(n-1))\\\\$

$S_n=\frac{3}{2}\times n+\frac{5}{6}\times \frac{n(n-1)}{2}\\\\$

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=\frac{3}{2}\times 12+\frac{5}{6}\times \frac{(12)(12-1)}{2}\\\\S_{12}=18+55\\\\S_{12}=73$

5 0

3 years ago

The graph that correctly represents the given system of equations is graph

sergij07 [2.7K]

Answer:

Step-by-step explanation:

The graph is represented graphically by drawing a point for each vertex and drawing an arc between two vertices if they are joined by an edge. If the graph is directed then...

6 0

3 years ago