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IgorC [24]
3 years ago
12

The circumstances of a circle is 15 π centimeters. What is the area of the circle in terms of π?

Mathematics
1 answer:
zalisa [80]3 years ago
8 0

Answer:

17.90493 is the area

Step-by-step explanation:

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Please answer this correctly
Andrej [43]
I believe the answer is 120. 3 5/6 turns into 3.833 when turned into a decimal. 3.833 would round up to 4 which is the nearest whole number. 34 3/7 would turn into 34.4285 as a decimal which turns into 30 when rounded to the nearest ten.
4 0
3 years ago
Solve each equation. Record your work and check your solution. <br> a. 5(x-2)+(-9)= -7(1-x)
Daniel [21]

The solution for equation is x = -6

<em><u>Solution:</u></em>

<em><u>Given equation is:</u></em>

5(x-2) + (-9) = -7(1-x)

We have to solve the equation

According to Bodmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right

Therefore, solve for brackets in given equation

5(x-2) + (-9) = -7(1-x)\\\\5x - 10 -9 = -7 + 7x

Solve for terms in left hand side of equation

5x - 19 = -7+7x

Move the variables to one side and constants to other side

7x -5x = -19+7\\\\2x = -12\\\\Divide\ both\ sides\ by\ 2\\\\x = -6

Thus the solution for equation is x = -6

8 0
3 years ago
Y=2x+3<br> solve for y<br> help me plz
ruslelena [56]

Answer:

this is already solved.

Step-by-step explanation:

the only thing left would be graphing it.

5 0
3 years ago
The number of ways in which 4 squares can be chosen at random on a chess board such that they lie on a diagonal line?.
wariber [46]

The number of ways is 364 if the number of ways in which 4 squares can be chosen at random.

<h3>What are permutation and combination?</h3>

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

It is given that:

On a chessboard, four squares are randomly selected so that they are adjacent to each other and form a diagonal:

The required number of ways:

= 2(2[C(4, 4) + C(5, 4) + C(6, 4) + C(7, 4)] + C(8, 4))

= 2[2[ 1 + 5 + 15+35] + 70]

= 364

Thus, the number of ways is 364 if the number of ways in which 4 squares can be chosen at random.

Learn more about permutation and combination here:

brainly.com/question/2295036

#SPJ4

5 0
1 year ago
Solve:<br> y" + 14y' + 49y = 8xe^-7x
erma4kov [3.2K]
The answer is 7x^2e-/8

8 0
3 years ago
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