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astraxan [27]
2 years ago
7

Which measurement would be least likely to be written in scientific notation

Mathematics
1 answer:
trapecia [35]2 years ago
7 0
The thickness in a dogs hair because depending on how skinny it is. it isn't going to be able to be measured in anything else. it would make the most sense
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Explain the steps that are necessary to solve 4x - 2(x + 3) = x + 1
Sidana [21]
So you would distribute what's in the parenthesis and end up with 4x-2x-6=x+1, then you combine like terms and end up with 2x-6=x+1, now you can add 6 to both sides or subtract 1 both sides (basically anything goes for this step just make sure you apply the same thing on both sides) so I'll add 6 and continue just to show you... then you end up with 2x=x+7 then you subtract 1x on both sides to get x=7. sorry it's a lot hopefully you get it know!
8 0
2 years ago
Read 2 more answers
If the end points of the diameter of a circle are (9,4) and (5,2) what is the standard form equation of the circle
timurjin [86]

Answer:

(x - 7)² + (y - 3)² = 5

Step-by-step explanation:

The center (h , k) is the midpoint of two end points of diameter

h = (9 + 5) / 2 = 7

k = (4 + 2) / 2 = 3

Equation of circle: (x - h)² + (y - k)² = r²

r = (√(9 - 5)² + (4 - 2)²) / 2 = √5

Equation: (x - 7)² + (y - 3)² = 5

6 0
3 years ago
Order 74.585, 74.586, 74.486, and 74.587 in decreasing order.
Veseljchak [2.6K]

Answer:

74.587, 74.586, 74.585, 75.486

Step-by-step explanation:

yes

6 0
2 years ago
Read 2 more answers
What is -4√12+√75 in the simplest radical form?
nekit [7.7K]

Answer: -3\sqrt{3}

Step-by-step explanation:

-4\sqrt{12} + \sqrt{75}

\sqrt{12} can be written as \sqrt{4} x \sqrt{3}

which is the same as 2\sqrt{3}

Also , \sqrt{75} can be written as \sqrt{25} x\sqrt{3} , which is the same as 5\sqrt{3}

Substituting into the main question , we have

-4 (2\sqrt{3} ) + 5\sqrt{3}

= -8\sqrt{3} + 5\sqrt{3}

= -3\sqrt{3}

3 0
3 years ago
A half-acre building lot is five times as long as it is wide. What are its dimensions?
Gnoma [55]

we know that

A half-acre is equal to----------> 2,023.43\ m^{2}

Let

x---------> the length side of the building lot

y--------> the width side of the building lot

A------> Area of the building lot

x=5y-------> equation 1

A=2,023.43\ m^{2}

A=x*y

2,023.43=x*y --------> equation 2

substitute equation 1 in equation 2

2,023.43=[5y]*y

5y^{2}= 2,023.43\\y^{2}= 404.686\\y= 20.11\ m

<u>Find the value of x</u>

x=5y---> x=5*20.11--> x=100.55 m

therefore

<u>the answer is</u>

the dimensions of the building lot are 100.55 m* 20.11 m

6 0
3 years ago
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