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3 years ago

Money all I really want is money 5+6x2=?

Mathematics

2 answers:

timofeeve [1]3 years ago

6 0

Answer:

Step-by-step explanation:

suter [353]3 years ago

6 0

Answer:

22 you welcome

Step-by-step explanation:

5+6 is 11

11x2=22

there's your answer

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Emily spent 1/2 of her money at the grocery store.Then, she spent 1/2 of what was left at the bakery. Next, at the music store,

Artist 52 [7]

I believe the answer is $48 because 6 * 2 is 12 and 12 * 2 is 24 and 24 * 2 is 48, thus 48$. Please feel free to check my work, though.

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3 years ago

√x+4=√3x A.) x=2 B.) x=-2 C.) x=3 D.) x=-3

Agata [3.3K]

I hope this helps you

6 0

3 years ago

Read 2 more answers

Given the function {f(x)=32-x}^{2}f(x)=32−x 2 , what is f(-5)f(−5)?

erastova [34]

Step-by-step explanation:

the description is very difficult to understand with special characters and potential typing errors.

I suspect the definition is

function(x) = 32 - x²

function(-5)function(-5) is then very easily calculated.

we need to calculate function(-5) and then square the result, as function(-5)function(-5) is just a simple multiplication of the function results.

function(-5) = 32 - (-5)² = 32 - 25 = 7

so,

function(-5)function(-5) = 7 × 7 = 49

4 0

3 years ago

Need all answers for 1, 2, 3, 4 , 5. Who ever answers them first will be mark brainliest!

Anettt [7]

answer

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EXPLANATION

5 0

3 years ago

The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p

VLD [36.1K]

Answer:

$3.13$

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

$\chi^2_{1-\frac{\alpha}{2}}= 51.770$

Chi square critical value for upper tail =

$\chi^2_{\frac{\alpha}{2}}= 81.085$

80% confidence interval:

$\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}$

Putting values, we get,

$=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13$

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0

3 years ago