sorry it can't fit the other half
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f(g(x))=362−x−2k f(g(x))=x→362−x−2k=x→x2−2x(1−k)−4(k−9)=0 Solution for x are equal if and only if discriminant Δ=0 4(1−k)2+16(k−9)=0 ... More
Answer: 100
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Answer:
no thank you
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Answer:
you bet
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