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NemiM [27]
3 years ago
5

Mrs. Wright bought some notebook paper for her class. She decided to keep 3/4 of the paper for her own use. How much paper did s

he have left to share with her students?
Mathematics
1 answer:
larisa [96]3 years ago
5 0
So the total amount of paper is 4/4 right?
And she kept 3/4.
So we have to minus 3/4 from 4/4.
Because it has the same denominator we need not change it to similar one.So 4-3 is one.
So answer is 1/4
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the point of M ( a, 4 ) is the midpoint of the line segment with endpoint at A(1,3) and B(5,b). Find the value of a and b
vazorg [7]

The value of a and b from the coordinates are 3 and 5 respectively

<h3>Midpoint of coordinates</h3>

The formula for finding the midpoint of two coordinates is expressed as;

M(x, y) = {x1+x2/2, y1+y1/2}

Given the following coordinates

M(a, 4)

A(1,3)

B(5,b)

Using the formula

a = 1+5/2

a = 6/2

a = 3

Similarly

4 = 3+b/2

8 = 3+b

b = 8-3

b = 5

Hence the value of a and b from the coordinates are 3 and 5 respectively

Learn more on midpoint here: brainly.com/question/18315903

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6 0
2 years ago
Read 2 more answers
HELP PLEASE HELP Please
mylen [45]
The answer is b, 5x^2 + 24x + 1
3 0
3 years ago
Please help me with this translating trigonometry graphs question. Brainliest and Points Available.
andreev551 [17]

According with the definition of translation, we conclude that the equations of graphs M and N are m(x) = f(x - 5) and n(x) = f(x) - 2, respectively.

<h3>How to apply translations on a given function</h3>

<em>Rigid</em> transformations are transformation such that the <em>Euclidean</em> distance of every point of a function is conserved. Translations are a kind of <em>rigid</em> transformations and there are two basic forms of translations:

Horizontal translation

g(x) = f(x - k), k ∈ \mathbb {R}     (1)

Where the translation goes <em>rightwards</em> for k > 0.

Vertical translation

g(x) = f(x) + k, k ∈ \mathbb {R}     (2)

Where the translation goes <em>upwards</em> for k > 0.

According with the definition of translation, we conclude that the equations of graphs M and N are m(x) = f(x - 5) and n(x) = f(x) - 2, respectively.

To learn more on translations: brainly.com/question/17485121

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3 0
2 years ago
A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

5 0
2 years ago
Solve and get brainliest!!<br>please be sure of your answer!!!!​
laila [671]

Answer:

hope this helps youuuuu

4 0
3 years ago
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