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NemiM [27]
3 years ago
5

Mrs. Wright bought some notebook paper for her class. She decided to keep 3/4 of the paper for her own use. How much paper did s

he have left to share with her students?
Mathematics
1 answer:
larisa [96]3 years ago
5 0
So the total amount of paper is 4/4 right?
And she kept 3/4.
So we have to minus 3/4 from 4/4.
Because it has the same denominator we need not change it to similar one.So 4-3 is one.
So answer is 1/4
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Find the equation of the linear function represented by the table below in slope intercept form.
grigory [225]

Answer:

y = -3x - 2

Step-by-step explanation:

slope (m) = (-8 - -5) / (2 - 1)   ... difference of y/difference of x

m = -3

y = mx + b

y = -3x + b

for (3,-11)    b = y + 3x = -11 + 3x3 = -2

equation: y = -3x - 2

5 0
3 years ago
Solve this system of linear equations. Separate
Gelneren [198K]

Answer:

x 2 y -4

Step-by-step explanation:

13x = -54 -20y give it is A

-10x = 60 + 20y give it is B

A + B the sum of the left side of equation is equal to the sum of the right side of equation

13 + (-10x) = -54 -20y + 60 + 20y

3x = 60-54

3x = 6

x=2

so put the x value in A or B equation you can receive y value (B is easier)

y = -4

7 0
3 years ago
I don't understand this
babunello [35]
Its DBC, cause two is in that point so you just find the answer choice with those three letters in the right order.
7 0
3 years ago
Read 2 more answers
The object on the right is made from a square-based pyramid joined to a cuboid.
spayn [35]

Answer:

Density of steel = 80.73 gm/cm^3

Step-by-step explanation:

The figure is made up of cuboid and square pyramid.

Height of cuboid, h = 9 cm

Length of cuboid, l = 6 cm

Width of cuboid, w = 6 cm

Volume of cuboid is given by the formula:

V_{Cuboid} = l \times w \times h

V_{Cuboid} = 6 \times 6 \times 9\\\Rightarrow V_{Cuboid} = 324\ cm^3

Density of Wood , D_{Cuboid}= 0.68g/cm^3

We know that formula of Density is:

Density = \dfrac{Weight}{Volume}

D_{Cuboid} = \dfrac{W_{Cuboid}}{V_{Cuboid}}\\\Rightarrow W_{Cuboid} = V_{Cuboid} \times D_{Cuboid}

Putting the values:

W_{Cuboid} = 324 \times 0.68 = 220.32\ gm

Total weight = W_{Cuboid} + W_{Pyramid}

970 = 220.32 + W_{Pyramid}

W_{Pyramid} = 749.68 gm

Volume of pyramid is given as:

V_{Pyramid}= \dfrac{1}{3} \times \text{Area of Base} \times \text{Vertical Height}

Base is a square with side 6 cm

V_{Pyramid}= \dfrac{1}{3} \times 6 \times 6 \times (17 -9)\\V_{Pyramid}= 96\ cm^3

Density of Steel/Pyramid:

D_{Pyramid} = \dfrac{W_{Pyramid}}{V_{Pyramid}}\\\Rightarrow D_{Pyramid} = \dfrac{749.68}{96}\\\Rightarrow D_{Pyramid} = 80.73\ gm/cm^3

5 0
3 years ago
What is the rule for this pattern? 1st term:32, 2nd term:36, 3rd<br>term:40​
Alenkasestr [34]

Answer:

Add four to each sum

Step-by-step explanation:

32, 36, 40

32 + 4 = 36

36 + 4 = 40

Rule: Add four to each sum

Hope this helped!

(Let me know if I got something wrong!)

4 0
3 years ago
Read 2 more answers
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