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3 years ago

Simultaneous EQUATION 3x+2y=16 2x+y=9 PLS HELP I need answer quickly

Mathematics

1 answer:

Serggg [28]3 years ago

6 0

Answer:

(2, 5 )

Step-by-step explanation:

Given the 2 equations

3x + 2y = 16 → (1)

2x + y = 9 → (2)

Multiplying (2) by - 2 and adding to (1) will eliminate the y- term

- 4x - 2y = - 18 → (3)

Add (1) and (3) term by term to eliminate y

- x = - 2 ( multiply both sides by - 1 )

x = 2

Substitute x = 2 into either of the 2 equations and solve for y

Substituting into (1)

3(2) + 2y = 16

6 + 2y = 16 ( subtract 6 from both sides )

2y = 10 ( divide both sides by 2 )_

y = 5

solution is (2, 5 )

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A farmer is constructing a rectangular pen with one additional fence across its width. Find the maximum area that can be enclose

konstantin123 [22]

The maximum area of the pen is the highest area the pen can have

The maximum area is 16200 square yards

Let the dimension be x and y.

So, the perimeter is given as:

$\mathbf{P = 360}$

Because it has one additional fence, the perimeter is calculated as:

$\mathbf{2x + y = 360}$

Make y the subject

$\mathbf{y = 360 - 2x}$

The area is calculated as:

$\mathbf{A = xy}$

Substitute $\mathbf{y = 360 - 2x}$

$\mathbf{A = x(360 -2x)}$

Expand

$\mathbf{A = 360x -2x^2}$

Differentiate

$\mathbf{A' = 360 -4x}$

Set to 0

$\mathbf{360 -4x = 0}$

Rewrite as:

$\mathbf{4x = 360}$

Divide both sides by 4

$\mathbf{x = 90}$

Substitute 90 for x in $\mathbf{A = 360x -2x^2}$

$\mathbf{A = 360 \times 90 - 2 \times 90^2}$

$\mathbf{A = 16200}$

Hence, the maximum area is 16200 square yards