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nasty-shy [4]
3 years ago
12

Algebra 2 please help

Mathematics
1 answer:
damaskus [11]3 years ago
8 0
I believe this is correct:
13 x^3-78x^2-234x

pleasa vote my answer brainliest. thanks!
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The expression 4h−3 factored is
lubasha [3.4K]

Answer:

prime

Step-by-step explanation:

this equation is not factorable

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3 years ago
I really don’t get what your supposed to do here please help i need to do it before 3PM
joja [24]
What is the question for this
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2 years ago
In a bag, Gary has 3 red marbles, 4 blue marbles, 7 yellow marbles, 5 green marbles, 6 purple marbles, and 8 clear marbles. What
miskamm [114]

Answer:

2220

Step-by-step explanation:

gcd of all numbers

3,4,7,5,6,8

2 = 3,2,7,5,3,4

2 = 3,1,7,6,3,2

2 = 3,1,7,5,3,1

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2 years ago
Rose Marie is shopping for some new shoes. The shoes she wants cost
ololo11 [35]

Answer:

Step-by-step explanation:

7 0
3 years ago
Suppose you are given either a fair dice or an unfair dice (6-sided). You have no basis for considering either dice more likely
hoa [83]

Answer: Our required probability is 0.83.

Step-by-step explanation:

Since we have given that

Number of dices = 2

Number of fair dice = 1

Probability of getting a fair dice P(E₁) = \dfrac{1}{2}

Number of unfair dice = 1

Probability of getting a unfair dice  P(E₂) = \dfrac{1}{2}

Probability of getting a 3 for the fair dice P(A|E₁)= \dfrac{1}{6}

Probability of getting a 3 for the unfair dice P(A|E₂) = \dfrac{1}{3}

So, we need to find the probability that the die he rolled is fair given that the outcome is 3.

So, we will use "Bayes theorem":

P(E_1|A)=\dfrac{P(E_1)P(A|E_1)}{P(E_1)P(A|E_1)+P(E_2)P(A|E_2)}\\\\(E_1|A)=\dfrac{0.5\times 0.16}{0.5\times 0.16+0.5\times 0.34}\\\\P(E_1|A)=0.83

Hence, our required probability is 0.83.

8 0
3 years ago
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