1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
neonofarm [45]
2 years ago
10

Halp me Vtxtvdcvdtcgdtgcgdtcgcvfg

Mathematics
1 answer:
gregori [183]2 years ago
7 0

Answer: 5578

Step-by-step explanation:

1058 + 4520 = 5578

You might be interested in
PLEASE HELP!! WILL GIVE BRAINLIEST!!!
Murrr4er [49]

Answer:

option D

Step-by-step explanation:

Jerry solved this equation: 

3(x-\frac{1}{4})=\frac{13}{6}

In the first step , she multiplied 3 inside the parenthesis

1. 3x-\frac{3}{4}=\frac{13}{6}

In step 2, 3/4 is added on both sides

2. 3x-\frac{3}{4}+\frac{3}{4}=\frac{13}{6}+\frac{3}{4}

In step 3, we take LCD 12

3. 3x=\frac{26}{12}+\frac{9}{12}

In step 4, add the fractions

4. 3x=\frac{35}{12}

Here, 3 or 3/1 are same.

\frac{3}{1}x=\frac{35}{12}

In step 5, to remove 3/1 we multiply both sides by 1/3.

Instead of multiplying 1/3 , Jerry made an error by multiplying 3/1

\frac{1}{3} \cdot \frac{3}{1}x=\frac{1}{3} \cdot \frac{35}{12}

x=\frac{35}{36}

In step 5, he should have multiplied both sides by 1/3

7 0
3 years ago
Read 2 more answers
Archimedes is making waves as he showers in his bath.
ch4aika [34]

Answer:

Step-by-step explanation

7 0
3 years ago
Read 2 more answers
Classify the triangle.<br> obtuse<br> equiangular<br> right<br> acute
horrorfan [7]

Answer:

Acute

Step-by-step explanation:

Note the definitions:

Obtuse: At least one of the angles are greater than 90°

Equilateral: All angles are congruent & equal to 60°

Acute: All angles are less than 90°

Right: At least one angle is equal to 90°

In this case, the triangle is a D) acute, for it fits the requirement for being an acute... all angles are less than 90°.

~

4 0
3 years ago
Read 2 more answers
The measure of angle A is 15°, and the length of side
dangina [55]

Answer:

Part 1) AB=30.9\ units

Part 2) AC=29.9\ units

Step-by-step explanation:

The picture of the question in the attached figure

Part 1

Find the length side AB

we know that

sin(A)=\frac{BC}{AB} ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

sin(15^o)=\frac{8}{AB}

solve for AB

AB=\frac{8}{sin(15^o)}=30.9\ units

Part 2

Find the length side AC

we know that

tan(A)=\frac{BC}{AC} ----> by TOA (opposite side divided by the adjacent side)

substitute the given values

tan(15^o)=\frac{8}{AC}

solve for AC

AC=\frac{8}{tan(15^o)}=29.9\ units

8 0
3 years ago
Eric drew a scale drawing of a country park. The scale he used was 1 inch = 2.5 yards. The picnic area is 80 yards wide in real
Alchen [17]
If 1 inch = 2.5 yards then
x inch = 80 yards
cross multiplying we have:
80 × 1 = x × 2.5
x = 80÷ 2.5 = 32 inches
therefore the picnic area is 32 inches in the drawing.
5 0
3 years ago
Other questions:
  • Write 2.346 as a percent to the nearest tenth of a percent
    11·1 answer
  • Which of the following is a solution to tanx+sqrt3=0?
    14·2 answers
  • The square tile has a side length of 10.5.What power can you write to represent the area of the tile?Write the power as an expre
    14·1 answer
  • Sales tax in Birmingham, AL, is the highest in the nation at 10 percent. Pete paid $9.44 in sales tax for an item in Birmingham,
    12·2 answers
  • Which is greater cube or triple??
    9·2 answers
  • What is the missing value to the nearest hundredth?
    9·2 answers
  • Which of these is best used for displaying frequency distributions that are close together and have categories within categories
    7·1 answer
  • One side of a regular triangle is 5 units. What is the perimeter of the triangle?
    8·2 answers
  • Help please due now I only have 10 mins..Help please!!! I only have 10 mins!!!​
    5·1 answer
  • A square picture frame has an area of 169 cm². Find the length, in cm, of the picture frame. ​
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!