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insens350 [35]
3 years ago
6

what do you call the middle value in the set of the data or quantities a mean b. median c.mode d.range​

Mathematics
1 answer:
MakcuM [25]3 years ago
6 0

Answer:

median is the middle value

mean is the average

mode is the one that occurs most

range is the highest number - lowest number

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Write one hundred and fourteen thousandths as a decimal number.
LiRa [457]

100.014. I think this is it

6 0
3 years ago
Find the sum of integers from 33 to 47:
ICE Princess25 [194]

Answer:

Step-by-step explanation:There are formulas to work this out, but you can also suss out an answer by a liberal application of critical thinking.

Okay, you want to add 51 + 52 + 53 + … + 99 + 100, right? (The … represents all the numbers in between, in case you were wondering.)

Well, that’s a total of 50 numbers. And if you know anything about addition, you know that it doesn’t matter what order you add them.

So you could also say 51 + 100 + 52 + 99 + 53 + 98 + … and so on.

Let’s see what happens. 51 + 100 = 151. So far so good.

Then, 52 + 99 also equals 151. And 53 + 98 also equals 151. Since there are 50 numbers, that’s 25 pairs that are going to add up to 151.

151 + 151 + 151 + 151 + … (21 more instances of 151).

So we can simplify our workload a bit. Instead of adding up all the numbers by hand, we can just multiply 151 by 25.

151 x 25 = 3775

From that, we can work out a generic formula that will allow you to add any sequence of numbers…without actually adding.

Let a be the first number in the sequence, and let n be the last number in the sequence. The number of numbers is (n - a) + 1. (You have to add 1, because if you just subtract, it’s like you’re losing the lowest number in the sequence).

So…you get the sum by adding the first and last number in the sequence, and then multiplying that result by half of the total number of numbers.

(a+n)((n−a)+12)  

an−a2+a+n2−an+n2  

−a2+a+n2+n2  

−a(a−1)+n(n+1)2  

Let’s check to see if it works!

−51(51–1)+100(100+1)2  

−51(50)+100(101)2  

−2550+10,1002  

75502  

3775  

Note that if the starting number were 1, the formula would simplify to  n(n+1)2

8 0
3 years ago
Read 2 more answers
I neeed held plzzzzzz
garik1379 [7]

Answer:

c

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
1 rectangle has a circumference of 72cm. If you reduce the width by 6cm and keep the same length, the area will decrease by 120c
WARRIOR [948]

Answer

the length is 20 cm and breadth is 16cm

Step-by-step explanation:

let, 2(a+b)= 72( as its the formulae of circumference)

here a is the length and b is the breadth

now total area is ab

according to the question

a(b-6)= ab-120

or -6a= - 120

so length is 20 cm

now by putting the value in the 1st eq we get

2(a+b)=72

or(a+b)=36

or 20+b=36

so breadth is 16 cm.

length is 20cm and breadth is 16 cm

(u can verify that easily)

thank u

5 0
2 years ago
Picture is attached above.​
Kamila [148]

Answer:

AAS

Step-by-step explanation:

AAS stands for Angle-Angle-Side. Here, you are given two angles and one side that is not included in the angles that are corresponding to the angles and side of another triangle, so they are congruent by the AAS rule.

You may be asking why the ASA (angle-side-angle) is not applicable. This is because the side in the ASA rule should be between the two angles, in this case, the 10-unit-side is not in between the two angles but rather nearer to the angle 70°, so ASA is not the right answer.

4 0
2 years ago
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