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4 years ago

I’m suppose to round 9955 to the nearest hundred but I don’t know how help please

Mathematics

1 answer:

Kobotan [32]4 years ago

4 0

Answer:

The answer would be 10,000.

Hope this helps!

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Find the area of the shaded sector.

Vladimir [108]

Given that,

Radius of the circle, r = 8.91 cm

Angle, $\theta=81^{\circ}$

To find,

The area of minor sector.

Solution,

The formula for the area of minor sector is given by the formula as follows :

$A=\dfrac{\theta}{360}\times \pi r^2\\\\A=\dfrac{81}{360}\times \pi \times (8.91)^2\\\\A=56.11\ \text{cm}^2$

So, the area of the shaded sector is $56.11\ \text{cm}^2$ .

8 0

3 years ago

Please help me out :)

arlik [135]

Answer:

$\frac{\sqrt{17} }{7}$

Step-by-step explanation:

Using the Pythagorean identity

sin²x + cos²x = 1, then

sinx = $\sqrt{1-cos^2x}$

Note that ( $\frac{4\sqrt{2} }{7}$ )² = $\frac{32}{49}$

sinΘ = $\sqrt{1-(32/49)}$

= $\sqrt{\frac{17}{49} }$ = $\frac{\sqrt{17} }{7}$

5 0

3 years ago

Write a division expression with a quotient that is: a. greater than 8÷0.001 b. less than 8÷0.001 c. between 8÷0.001 and 8÷ 1 10

VMariaS [17]

9÷0.001 is greater than 8÷0.001.
7÷0.001 is less than 8÷0.001.
8÷0.002 lie between 8÷0.001 and 8÷110.

7 0

3 years ago

Examplelt: A wall of length 10 m was to be built across an open ground. The height of the wall is 4 m and thickness of the wall

harina [27]

Answer :

4167 bricks.

Explanation :

Since the wall with all its bricks makes up the space occupied by it, we need to find the volume of the wall, which is nothing but a cuboid.

Here,

${\qquad \dashrightarrow{ \sf{Length=10 \: m=1000 \: cm}}}$

$\qquad \dashrightarrow{ \sf{Thickness=24 \: cm}}$

$\qquad \dashrightarrow{ \sf{Height=4 m=400 \: cm}}$

Therefore,

${\qquad \dashrightarrow{ \bf{Volume \: of \: the \: wall = length \times breadth \times height}}}$

${\qquad \dashrightarrow{ \sf{Volume \: of \: the \: wall = 1000 \times 24 \times 400 \: {cm}^{3} }}}$

Now, each brick is a cuboid with Length = 24 cm, Breadth = 12 cm and height = 8 cm.

So,

${\qquad \dashrightarrow{ \bf{Volume \: of \: each \: brick = length \times breadth \times height}}}$

${\qquad \dashrightarrow{ \sf{Volume \: of \: each \: brick = 24 \times 12 \times 8 \: {cm}^{3} }}}$

So,

${\qquad \dashrightarrow{ \bf{Volume \: of \: bricks \: required = \dfrac{volume \: of \: the \: wall}{volume \: of \: each \: brick} }}}$

${\qquad \dashrightarrow{ \sf{Volume \: of \: bricks \: required = \dfrac{1000 \times 24 \times 400}{24 \times 13 \times 8} }}}$

${\qquad \dashrightarrow{ \sf{Volume \: of \: bricks \: required = \bf \: 4166.6} }}$

Therefore,

<u>The wall requires 4167 bricks. </u>

6 0

2 years ago

Write a sentence for the equation x^3=2(y+3)

solniwko [45]

Answer:

Do you mean strandord or expanded form?

Step-by-step explanation:

7 0

3 years ago