Answer:
positive 3
Step-by-step explanation:
it's going up by 1 and left by 3
Answer:
infinite solutions
Step-by-step explanation:
Answer:
As shown below
Step-by-step explanation:
Given that when X denotes the errors in an experimental transmission channel, when checked by a certifier that detects missing pulses. follows the cumulative density function as given below:
Answer:
0.1319 or 13.2%
Step-by-step explanation:
You can solve this using the binomial probability formula.
The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.
Then, we can set the equation as follows:
P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k)
n=4, x=2, k=2
when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157
when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154
when x=4 (4 4)(1/6)^4(5/6)^4-4 = 0.0008
Add them up, and you should get 0.1319 or 13.2% (rounded to the nearest tenth)
